<span>1) supplementary angles => sum of angles' measure is 180°
Two lines intersecting creating four angles with the left obtuse angle labeled one and the acute angle to the right labeled two
= > angle 1 + angle 2 = 180°
Then those two match.
2) complementary angles => sum of the two angles = 90°
Two lines intersecting in a right angle with a square indicating a right
angle in quadrant one and a ray splitting quadrant two with a two
labeling the left angle and one labeling the angle on the right
=> angle 2 + angle 1 = 90°
Then those two match
3) vertical angles
Two parallel horizontal lines intersected by a vertical line with a
square indicating a right angle in quadrant one of the top line and a
one labeling the angle in quadrant two and two labeling quadrant four of
the top line
Those two matches because the angle label 1 and the angle label 2 are vertical angles as per the definittion.
4) adjacent angles
Two lines intersecting in a V shape with the left angle of one hundred fifty seven degrees and a bottom angle of X degrees
Those two match becasue the angle of 157° and the angle of X° are adjacent.
</span>
Hello from MrBillDoesMath!
Answer:
f(-1) = 2
f(1) = 6
f(2) = 11
Discussion:
Let f(x) = 2x^3 - 3x^2 + 7. Then
f(-1) = 2 (-1)^3 - 3 (-1)^2 + 7 = -2 -3 + 7 = -5 + 7 = 2
f(1) = 2(1)^3 - 3(1)^2 + 7 = 2 -3 + 7 = -1 +7 = 6
f(2) = 2(2)^3 - 3(2)^2 + 7 = 2*8 - 3*4 + 7 = 16-12+7 = 11
Thank you,
MrB
Answer:
i believe it only has one solution, which would be x=12.
Step-by-step explanation:
Answer: 10 pans
Step-by-step explanation:
<u>Step 1:</u>
If the number of biscuits needed= 80
<u>Step 2:</u>
And the number of biscuits on each pan= 8
<u>Step 3:</u>
Then the number of pans needed= 80 ÷ 8
Answer: 80 ÷ 8 = 10pans
Domain: Every possible x value.
Range: Every possible y value.
Answer:
Domain: [-5,-3)⋃(-2,4]
Range: [-1,4]
Remember that when there is unfilled dot on the graph that means whatever the number is there on x and y isn't being used which you can follow it by ) not ]. Although Y=2 isn't used on the right function but there is value for Y on the left one which is equal to X=-4 and the same goes for Y=3. On the other hand when it comes for the X=-3, that's not a part of the domain neither the X=-2.