Question

Please help me

Answer 1

Answer: A and D are the correct statements.

1. In ΔBRS and ΔBDC

∠R=∠D and ∠S=∠C [∵ corresponding angles]

So by AA similarity criteria ,

△BCD is similar to △BSR.

2. As RS is parallel to DS then by basic proportionality theorem,

$\frac{BR}{RD}=\frac{BS}{SC}$

⇒ B is not true.

3. As we can see BC is greater than BS ,so it cannot possible.

If $\frac{BR}{BD}=\frac{2}{3}$ and $\frac{BR}{BD}=\frac{BS}{BC}$

where BS=6 then $\Rightarrow\frac{2}{3}=\frac{6}{BC}\\\Rightarrow\ BC=9$.

4. As RS is parallel to DS then by basic proportionality theorem,

$\frac{BR}{RD}=\frac{BS}{SC}$

⇒BR×SC=RD×BS.

5. From 4 its not true that BR/RS = BS/SC.

Answer 2

the answer for the question is 1,2 and 4