Alright, we're dealing with a few values here, so let's give them some labels to save us some trouble down the road. We'll call the number of messages sent by Maria <em>m</em>, the number sent by Bill <em>b</em> and the number sent by Change (is that a real name?) <em>c</em>. We don't know exactly what each number is, but let's take a look at what information they do give us.
Change sent 2 times as many messages as Bill, or, using our variable for Change and Bill:

We're also given that Maria sent 7 messages more than Bill, which we can represent with:

Notice that <em>m</em> and <em>c</em> are both in terms of <em>b</em>. We can use this for our next step. We're given at the beginning that together, Maria, Bill, and Change sent 71 messages over the weekend. As an equation using all of our variables, this translates to:

Since <em>m </em>and <em>c </em>are both in terms of <em>b</em>, we can substitute those expressions in and solve for <em>b</em>:

Now that know that Bill sent 16 texts, we can find the numbers for Change and Maria:

So,
Bill sent 16 texts, Maria sent 23, and Change sent 32.
To solve this problem, we can set two equations.
Let x be the cost of coffee and y be the cost of latte.
Two coffees and one latte: 2x + y = 10.50
y=10.50 - 2x ...(1)
Three coffees and two lattes: 3x + 2y = 17.00...(2)
Put (1) into (2), we have:
3x + 2(10.50-2x) = 17.00
3x + 2(10.50) - 2(2x) = 17.00
3x + 21 - 4x = 17
Put the unknown to one side:
3x -4x = 17 - 21
-x = -4
When there are negative numbers on both sides, we can take the negative signs away:
x= 4
Therefore, cost of one coffee is A. $4.00.
Hope ot helps!
Xy
-5.510
-4.58
-3.56
-2.54
-1.52
2 tickets cost $8.10. 1 ticket is $4.05. Just multiply the money he has by .6 for 2 tickets and then divide the number you get by 2 for the price of 1 ticket. Hope this helps!
Answer:
The answer would be z/6 + 5 - 8.
Step-by-step explanation:
Quotient means the answer to a division problem, so we know that z and 6 must be divided. Then it tells us to add 5 to the quotient and then subtract 8 from the total. Because of PEMDAS no parentheses are needed.