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3 years ago

How many regular triangles meet at a vertex to form a regular tessellation?

Mathematics

2 answers:

erastovalidia [21]3 years ago

7 0

D.) Six regular triangles meet at a vertex to form a regular tessellation

Hope this helps!

nirvana33 [79]3 years ago

4 0

6 regular triangles meet at vertex to form a regular tessellation.

Answer is D.

Hope it helps!

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Jackson buys a grape snow cone on a hot day. By the time he eats all the "snow" off the top, the paper cone is filled with 27\pi

anyanavicka [17]

Question:

Jackson buys a grape snow cone on a hot day. By the time he eats all the "snow" off the top, the paper cone is filled with 27\pi27π27, pi cm^3 3 start superscript, 3, end superscript of melted purple liquid. The radius of the cone is 333 cm. What is the height of the cone?

Answer:

The height of the cone is $9 \ cm$

Explanation:

It is given that the radius of the cone is $3 \ cm$

The volume of the cone is $27\pi$

The height of the cone can be determine using the formula,

$V=\frac{1}{3} \pi r^{2} h$

Substituting the values $V=27 \pi$ and $r=3$ , we get,

$27 \pi=\frac{1}{3} \pi(3)^{2} h$

Multiplying both sides by 3, we have,

$81 \pi= 9\pi h$

Dividing both sides by $9 \pi$ , we have,

$9=h$

Thus, the height of the cone is $9 \ cm$

4 0

3 years ago

11 minus what number is 7

MA_775_DIABLO [31]

Eleven minus four equal seven
11-4=7

4 0

3 years ago

Quadrilateral ABCD is similar to Quadrilateral EFGH. The scale factor is 3:2 if AB = 18, find EF

Marina86 [1]

Answer:

A... 12

Step-by-step explanation:

5 0

2 years ago

The area of the shaded segment is 100cm^2. Calculate the value of r.

Reil [10]

Hello,

The formula for finding the area of a circular region is: $A= \frac{ \alpha *r^{2} }{2}$

then:
$A_{1} = \frac{80*r^{2} }{2}$

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

$cos(40)= \frac{h}{r} \\ \\ h= r*cos(40)\\ \\ \\ sen(40)= \frac{b}{r} \\ \\ b=r*sen(40)$

Now we can find its area:
$A_{2}=2* \frac{b*h}{2} \\ \\ A_{2}= [r*sen(40)][r*cos(40)]\\ \\A_{2}= r^{2}*sen(40)*cos(40)$

The subtraction of the two areas is 100cm^2, then:

$A_{1}-A_{2}=100cm^{2} \\ (40*r^{2})-(r^{2}*sen(40)*cos(40) )=100cm^{2} \\ 39.51r^{2}=100cm^{2} \\ r^{2}=2.53cm^{2} \\ r=1.59cm$

Answer: r= 1.59cm

7 0

3 years ago

Read 2 more answers

What’s the value of the underlined digit in each number? 0.679 1.556 6.8

Aleks [24]

For the first 6, we see that it is exactly one place behind the decimal point, therefore meaning that it is in the tenths place. The second 6 is three places behind the decimal place making it in the thousandths place. The third and final 6 is one place in front of the decimal, therefore it is in the ones place. Hope this helps!

7 0

3 years ago