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katrin2010 [14]
3 years ago
6

How many regular triangles meet at a vertex to form a regular tessellation?

Mathematics
2 answers:
erastovalidia [21]3 years ago
7 0
D.) Six <span>regular triangles meet at a vertex to form a regular tessellation

Hope this helps!</span>
nirvana33 [79]3 years ago
4 0
6 regular triangles meet at vertex to form a regular tessellation.

Answer is D.

Hope it helps!
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Help me with this problem please.
melomori [17]

Answer:

your the problem

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
What is the angles mSRW?
Scilla [17]

Answer:

126°

Step-by-step explanation:

(2x +18)° = (3x)°

2x + 18 = 3x

18 = 3x - 2x

18 = x

therefore, (3x)° = (3*18)°= (54)°

m\angle SRW + (3x)\degree = 180\degree \\m\angle SRW + 54\degree  = 180\degree \\m\angle SRW = 180\degree  - 54\degree  \\\huge\red{\boxed{m\angle SRW = 126\degree}}

5 0
3 years ago
Mr. Hayden's Bible class collected $11
ki77a [65]

This is the only way I can think of this mathematically. This took a good 20 minutes for me. You need to guess and check. Like try 17 quarters, 50 nickels, and 37 dimes etc. until you get 11.00. My numbers are mathematically correct but we both know you cant have 18.909 quarters so. lol

Answer:

Quarters: 18.909

Nickels: 49.818

Dimes: 37.818

Somewhere around those numbers.

Step-by-step explanation:

$11.00 total in coins

Nickel = $0.05

Dime = $0.10

Quarter = $0.25

(n*0.05) + (d*0.10) + (q*0.25)

Solve the equation for q.

q=\frac{1}{2} d

(n*0.05) + (d*0.10) +( \frac{1}{2} d *0.25)

Simplify the expression.

9d + 2n = 440

d - n = -12

Multiply both sides of the equation by -9.

-9d + 9n = 108

9d + 2n = 440

Sum the equations vertically to eliminate at least one variable.

11n = 548

n=\frac{548}{11}

Substitute the given value of n into the equation d - n = -12

d-\frac{548}{11} =-12

d=\frac{416}{11}

Substitute the given value of n into the equation q=\frac{1}{2} d

q=\frac{1}{2} *\frac{416}{11}

q=\frac{208}{11}

Finally

d=\frac{416}{11}        d = 37.818

n=\frac{548}{11}        n = 49.818

q=\frac{208}{11}        q = 18.909

6 0
2 years ago
My soccer team has 16 players. I have to choose a starting lineup of a goalie and 10 regular players (the regular players are in
ASHA 777 [7]

Answer:

3003

Step-by-step explanation:

We want to find out how many ways we can choose 10 players among 15 players (since the goalie is not interchangeable)

The number of different lineups you can have can be found by using combination:

^{15}C_{10} = \frac{15!}{(15 - 10)! 10!}\\ \\= \frac{15!}{5! * 10!} \\\\= 3003

There are 3003 different lineups that can be chosen.

6 0
3 years ago
ABC is dilated using a scale factor of 2.5. Which property does not change?
Lorico [155]
C..................................................
8 0
2 years ago
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