H = –16t2 + 156t + 105, when t = t', the time where the rocket hit the ground after it is launched, so 105= –16t'2 + 156t' + 105, so -16t'2 + 156t' = 0 implies t' =0 or -16t'+ 156= 0, equivalent to t'=9.75, so the answer is
b) <span>9.8 s</span>
in the number line, the end points are DG, and the point in between is O
DG = 88
DO = 5x + 12
OG = 2x
Set the equation. The two parts (DO & OG) are equal to the whole (DG)
2x + 5x + 12 = 88
Simplify. Combine like terms
(2x + 5x) + 12 = 88
7x + 12 = 88
Isolate the x. Remember to do the opposite of PEMDAS. Subtract 12 from both sides
7x + 12 (-12) = 88 (-12)
7x = 76
Isolate the x. Divide 7 from both sides:
7x/7 = 76/7
x = 76/7
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Find DO. Plug in "76/7" for x:
DO = 5x + 12
DO = 5(76/7) + 12
Simplify. Remember to follow PEMDAS. Multiply 76 with 5
DO = 380/7 + 12
Next, divide 380 with 7
DO = 54.29 (rounded)
Finally, add
DO = 54.29 + 12
DO = 66.29
66.29 is your answer
hope this helps
Answer:
2
Step-by-step explanation:
5*2=10
10+10=20
or
5*x+10=20
10-10=0
20-10=10
5*x=10
5/5=0
10/5=2
x=2
Answer:
$$$$$$$$ the anwser is 4 i think thats how you solve it
Step-by-step explanation:
