Answer: there are eight bicycles and 7 tricycles.
Step-by-step explanation:
Let x represent the number of bicycles that are there.
Let y represent the number of tricycles that are there.
There are a total of 15 bicycles and tricycles. This means that
x + y = 15
A bicycle has 2 wheels and a tricycle has 3 wheels. There are 37 wheels all together if we count them up. This means that
2x + 3y = 37- - - - - - - - - - - - - 1
Substituting x = 15 - y into equation 1, it becomes
2(15 - y) + 3y = 37
30 - 2y + 3y = 37
- 2y + 3y = 37 - 30
y = 7
x = 15 - y = 15 - 7
x = 8
Y/3=x or y divided by 3 is equals x. They are the same thing just but the equation in word form.
You can draw two quarters, a dime, a nickel, and three pennies. Or 6 dimes and 8 pennies.
Answer:
Option A
The p-value is less than the significance level of 0.05 chosen and so we reject the null hypothesis H0 and can conclude that the proportion of the subjects who have the necessary qualities is less than 0.2.
Step-by-step explanation:
Normally, in hypothesis testing, the level of statistical significance is often expressed as the so-called p-value. We use p-values to make conclusions in significance testing. More specifically, we compare the p-value to a significance level "α" to make conclusions about our hypotheses.
If the p-value is lower than the significance level we chose, then we reject the null hypotheses H0 in favor of the alternative hypothesis Ha. However, if the p-value is greater than or equal to the significance level, then we fail to reject the null hypothesis H0
though this doesn't mean we accept H0 automatically.
Now, applying this to our question;
The p-value is 0.023 while the significance level is 0.05.
Thus,p-value is less than the significance level of 0.05 chosen and so we reject the null hypothesis H0 and can conclude that the proportion of the subjects who have the necessary qualities is less than 0.2.
The only option that is correct is option A.
Answer:
C. x + 9 = 11
Step-by-step explanation:
We are trying to identify which of the equations does not match with the others. In this case, solve for x in each equation:
Option A):
6 + x = 9
Subtract 6 from both sides:
6 (-6) + x = 9 (-6)
x = 9 - 6
x = 3
Option B):
15 = x + 12
Subtract 12 from both sides:
15 (-12) = x + 12 (-12)
15 - 12 = x
x = 3
Option C):
x + 9 = 11
Subtract 9 from both sides:
x + 9 (-9) = 11 (-9)
x = 11 - 9
x = 2
Option D):
7 + x = 10
Subtract 7 from both sides:
x + 7 (-7) = 10 (-7)
x = 10 - 7
x = 3
---------------------------------------------------------------------------------------------------------
As you can tell, all the equations end with x = 3 as there answers except C. x+9=11, making (C) your answer.
~
