The method doubleVal() is created to accept a single parameter of type double.
It multiplies what ever the value of the parameter is and returns the resulting value.
In this question The method is called within this output statement System.out.println(doubleVal(val)); (Note that val had already been declared and assigned the value of 6.5)
The value 6.5 is doubled and outputed to the screen
I would tell said individual to stop what they’re trying to tell me because if it’s not stuff I should know about or want to hear about then I don’t wanna hear any of it
