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3 years ago

The figures shown are similar

Mathematics

2 answers:

Usimov [2.4K]3 years ago

5 0

Answer:

The answer is A I TOOK THE TEST

Step-by-step explanation:

9966 [12]3 years ago

3 0

The answer is A

3/4

good luck

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Helppp!

lilavasa [31]

Answer:

It's the the 4th one. 6.3.3

5 0

2 years ago

Delilah does 841 jumping jacks in 4 minutes. She does her jumping jacks at a constant rate. How many jumping jacks can Delilah d

STatiana [176]

841 jumping jacks per 4 minutes

$\frac{841~jumping~jacks}{4~minutes}$

Divide both sides by 4.

$\frac{841}{4} \div \frac{4}{4} = \frac{210.25}{1}$

Delilah can do 210.25 (or 210) jumping jacks per minute.

4 0

4 years ago

From families with four children a family is chosen at random. Let X be the number of boys in the family. Calculate and sketch t

alisha [4.7K]

Solution :

Given :

X = the number of boys in a family of four children

Families having four children are chosen randomly.

The gender distribution in the four child family are equally probable.

Thus,

X P(X) CDF

0 $^4C_0 (1/2)^{4}$ = 1/16 $\frac{1}{16}$

1 $^4C_1 (1/2)^{4}$ = 1/4 $\frac{5}{16}$

2 $^4C_2 (1/2)^{4}$ = 3/8 $\frac{11}{16}$

3 $^4C_3 (1/2)^{4}$ = 1/4 $\frac{15}{16}$

4 $^4C_4 (1/2)^{4}$ = 1/16 1

4 0

3 years ago

20 points for one question. You know you want to.

spayn [35]

Answer:

The answer is A.

Step-by-step explanation:

We only have to test one coordinate to find the answer. The original coordinate for N is (-1, -1). Using the formula, N' is (0, -2).

8 0

4 years ago

Read 2 more answers

In a 3M Privacy Filters poll, 806 adults were asked to identify their favorite seat when they fly, and 492 of them chose a windo

Snowcat [4.5K]

Answer:

Step-by-step explanation:

If majority of adults prefer a window seat when they fly, it means that more than half or more than 0.5 of the population prefer a window seat when they fly.

We would set up the hypothesis test.

For the null hypothesis,

p = 0.45

For the alternative hypothesis,

p > 0.5

Considering the population proportion, probability of success, p = 0.5

q = probability of failure = 1 - p

q = 1 - 0.5 = 0.5

Considering the sample,

Sample proportion, P = x/n

Where

x = number of success = 492

n = number of samples = 806

P = 492/806 = 0.61

We would determine the test statistic which is the z score

z = (P - p)/√pq/n

z = (0.61 - 0.5)/√(0.5 × 0.5)/806 = 6.24

From the normal distribution table, the p value < 0.00001

Since alpha, 0.01 < than the p value, then we would reject the null hypothesis. Therefore, at a 1% significance level, we can conclude that the majority of adults prefer a window seat when they fly.

8 0

3 years ago