If the weight of the bottom box is b then the weight of a stack of four boxes is b + b/2 + b/4 + b/8
= 8b/8 + 4b/8 + 2b/8 + 1b/8
= 15/8 b
A stack must weigh less than 100 pounds
15/8 b < 100
b < 100 x 8/15 = 53 1/3 pounds
If boxes have a minimum weight of 1 pound then
for stacks that contain 4 boxes the range of b is [8, 53 1/3)
and if stacks contain 1 to 4 boxes the range of b is [1, 53 1/3)
If the only restriction is a maximum of 100 then the range of b is [0, 53 1/3)
60-(16.98+14.99+21.95)=change=60-53.92=6.08
change is $6.08
Step-by-step explanation:
I assume that "ground" is at 0 ft height. which is in an actual scenario not airways the case.
y = -16x² + 64x + 89
shows us that the tower is 89 ft tall (the result for x = 0, at the start).
anyway, if the original assumption is correct, then we need to solve
0 = -16x² + 64x + 89
the general solution for such a quadratic equation is
x = (-b ± sqrt(b² - 4ac))/)2a)
in our case
a = -16
b = 64
c = 89
x = (-64 ± sqrt(64² - 4×-16×89))/(2×-16) =
= (-64 ± sqrt(4096 + 5696))/-32 =
= (-64 ± sqrt(9792))/-32
x1 = (-64 + 98.95453501...)/-32 = -1.092329219... s
x2 = (-64 - 98.95453501...)/-32 = 5.092329219... s
the negative solution for time is but useful here (it would be the time calculated back to ground at the start).
so, x2 is our solution.
the rocket hits the ground after about 5.09 seconds.
Answer:
x<3/-2
Step-by-step explanation:
4x>6x+3
4x-6x>3
-2x>3
x<3/-2
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