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3 years ago

Find the value of x in the triangle shown below

Mathematics

1 answer:

kari74 [83]3 years ago

8 0

Answer: 70

Step-by-step explanation:

Since the spot where the 3.5 and the 4 meet is 55 and there is 2 of that exact angle you can add them to get 110. 180-110 is 70 :)

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Help! Due soon!!!!!!!!!

denis23 [38]

Answer:

78.75

Step-by-step explanation:

450 is increased by 75%

450 + 450*75%

Change to decimal form

450 +450*.75

450+337.5

787.5

Now decrease by 90%

787.5-787.5*90%

Change to decimal form

787.5-787.5*.9

787.5-708.75

78.75

8 0

2 years ago

Read 2 more answers

What is 2x-64<108 If you answer this I will give you a total of 23 points!

alexandr1967 [171]

Answer:

2x-64<108

One solution was found :

x < 86

Rearrange:

Rearrange the equation by subtracting what is to the right of the greater than sign from both sides of the inequality :

2*x-64-(108)<0

Step by step solution :

Step 1 :

Pulling out like terms :

1.1 Pull out like factors :

2x - 172 = 2 • (x - 86)

Equation at the end of step 1 :

Step 2 :

2.1 Divide both sides by 2

Solve Basic Inequality :

2.2 Add 86 to both sides

x < 86

4 0

3 years ago

Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste

lidiya [134]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$ In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$ And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

Solution to the problem

For this case we have the following distribution given:

X 3 4 5 6

P(X) 0.07 0.4 0.25 0.28

We can calculate the mean with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$

In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$

And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

3 0

3 years ago

Why did the kindergartener take her books to the zoo

Shalnov [3]

So the kindergartner could show animals pictures. XD JK

3 0

2 years ago

Can someone please help me with this?

viktelen [127]

Answer:

Step-by-step explanation:

hopes this helps i have a F in math so not sure

6 0

2 years ago