Answer:
the x coordinate is 1
the y coordinate is 1
Step-by-step explanation:
Answer: The answer is 12.5 ft.
Step-by-step explanation: Given that there is a rectangle with ratio of its length to breadth 8 : 5. Also, the longer side of the rectangle is 20 feet. We are to find the length of the shorter side.
Let, '8x' and '5x' be the length and breadth of the rectangle respectively. Since length is the longer side, so we have
![8x=20\\\\\Rightarrow x=\dfrac{20}{8}\\\\\\\Rightarrow x=2.5.](https://tex.z-dn.net/?f=8x%3D20%5C%5C%5C%5C%5CRightarrow%20x%3D%5Cdfrac%7B20%7D%7B8%7D%5C%5C%5C%5C%5C%5C%5CRightarrow%20x%3D2.5.)
Therefore, width, length of the shorter side will be
![W=5x=5\times 2.5=12.5~\textup{ft.}](https://tex.z-dn.net/?f=W%3D5x%3D5%5Ctimes%202.5%3D12.5~%5Ctextup%7Bft.%7D)
Thus, the length of the shorter side is 12.5 ft.
q = 10p because all of them are multiplied by ten
Answer:
Total number of ways to select all sstudent to make assignment = 10×36×70×1 = 25200
Step-by-step explanation:
We have given number of students = 10
These 10 students are assigned to four dorm rooms a single, a double, a triple and a quad
So number of ways to assigned single student ![=^{10}C_1=\frac{10!}{1!9!}=10\\](https://tex.z-dn.net/?f=%3D%5E%7B10%7DC_1%3D%5Cfrac%7B10%21%7D%7B1%219%21%7D%3D10%5C%5C)
Now left student = 10 -1 = 9
So number of ways to assigned double student ![=^{9}C_2=\frac{9!}{2!7!}=36](https://tex.z-dn.net/?f=%3D%5E%7B9%7DC_2%3D%5Cfrac%7B9%21%7D%7B2%217%21%7D%3D36)
Now left student = 9-2 = 7
So number of ways to assigned triple student
=70
Now left student = 7 - 3 = 4
So number of ways to assigned quad student ![=^{4}C_4=\frac{4!}{4!0!}=1](https://tex.z-dn.net/?f=%3D%5E%7B4%7DC_4%3D%5Cfrac%7B4%21%7D%7B4%210%21%7D%3D1)
So total number of ways to select all sstudent to make assignment = 10×36×70×1 = 25200