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ludmilkaskok [199]
3 years ago
10

Strengthening a response by removing an unpleasant consequence is called

Advanced Placement (AP)
2 answers:
kozerog [31]3 years ago
6 0
Extinction? I may be wrong.
NNADVOKAT [17]3 years ago
4 0

negative reinforcement

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A star is observed from two positions of Earth in its orbit, in summer and winter. Which of these is the best method to calculat
Bezzdna [24]

Answer:

The answer is "measure the parallax and use it in calculations".

Explanation:

In this question, the above choice is correct because, in the summer and winter, light is observed from both parts of a planet. An astronomer can once, again and 6 weeks later calculate the position of a star and then compute the perceived shift of location. It measures which utilizes parallax and its best method for calculating the approximate distance between the star, as well as the planet.

8 0
2 years ago
The graph of f(x) = 1/x cos
nikitadnepr [17]

Answer:

D. f(x) exist for all real numbers where  x ≤ -1  or x ≥ 1

Explanation:

You can't divide by 0 and

You can't have a negative squareroot.

So solve for when x=0 for the denominator,

and when is x<0 for the squareroot.

4 0
3 years ago
Urban planners need a community college or two year degree. True or false?
miss Akunina [59]

False you need 4 year undergraduate and a 2 year graduate

8 0
3 years ago
Anong ahensya ang itinalaga ng pamahalaang pangulo sa pangangasiwa ng ating kalikasan at kapaligiran nito
Paha777 [63]

Answer:

Department of Environment and Naturally Resources/Kagawaran ng Kapaligiran at Likas na Yaman.

6 0
3 years ago
Particle x moves along the positive x-axis so that its position at time t ~ 0 is given by x(t) = 5t 3 - 9t 2 + 7. at what time t
Arada [10]

Answer: 1.2 seconds

Explanation:

$$At the farthest point the velocity of particle will be zero. \ Differentiating the given equation of position and equating it with zero:$$\begin{aligned}x(t) &=5 t^{3}-9 t^{2}+7 \\x^{\prime}(t) &=15 t^{2}-18 t \\0 &=15 t^{2}-18 t \\t(15 t-18) &=0 \\t &=0 \\t &=\frac{18}{15}=1.2 \mathrm{~s}\end{aligned}$$

$$Thus, at $t=1.2 \mathrm{~s}$ particle will be at the farthest point. \\\\\underline{Justification:}\\The particle moves towards the left from $t \in[0,1.2)$. After that particle keeps moving in  the positive x-direction.

5 0
2 years ago
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