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Butoxors [25]
3 years ago
7

Elijah has some dimes and some quarters. He has a minimum of 18 coins worth at most $3.60 combined. If Elijah has 12 dimes, dete

rmine the maximum number of quarters that he could have. If there are no possible solutions, submit an empty answer.
Mathematics
1 answer:
marysya [2.9K]3 years ago
3 0

Answer:

6

Step-by-step explanation:

So, 12 dimes is 120 cents. 120 cents is $1.20. You said he had 18 coins, and 12 dimes takes away 12 coins. So the only number left is 6. (I think)

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Step-by-step explanation:

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The play director spent 190190190 hours preparing for a play. That time included attending 353535 rehearsals that took varying a
dybincka [34]

Answer:

The equation 35x+93\frac{3}{4} =190 gives average time spent on 35 rehearsals.

Step-by-step explanation:

We are supposed to find that what question does the equation 35x+93\frac{3}{4} =190 finds answer of.

We can see that 35x represents time spent on 35 rehearsals and 93\frac{3}{4} is time spent on other responsibilities related to play. The sum of these times equals to total time spent on preparing the play.

Now let us solve our equation step by step.

35x+\frac{375}{4} =190

After subtracting 93\frac{3}{4} hours from 190 hours we will get time spent on 35 rehearsals.

35x =190-\frac{375}{4}

35x =\frac{760-375}{4}

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Time spent on 35 rehearsals is 96.25 hours and we are told that each rehearsal took different amount of time. Dividing 96.25 by 35 we will get average time spent on each rehearsal.

x =\frac{96.25}{35}=2.75  

Therefore, equation 35x+93\frac{3}{4} =190 finds average time spent on 35 rehearsals.


7 0
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vampirchik [111]
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Step-by-step explanation:

The arc length is calculated as

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Answer: player number one

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Player number one starts with one and then he waits for player number two.

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3 years ago
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