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Butoxors [25]
3 years ago
7

Elijah has some dimes and some quarters. He has a minimum of 18 coins worth at most $3.60 combined. If Elijah has 12 dimes, dete

rmine the maximum number of quarters that he could have. If there are no possible solutions, submit an empty answer.
Mathematics
1 answer:
marysya [2.9K]3 years ago
3 0

Answer:

6

Step-by-step explanation:

So, 12 dimes is 120 cents. 120 cents is $1.20. You said he had 18 coins, and 12 dimes takes away 12 coins. So the only number left is 6. (I think)

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At the end of a film, the year is given in Roman numerals.
dem82 [27]

Answer:

MMVI=2006 M MEANS 1000 AND ONE MORE M MEANS 1000 TOTAL 2000 THEN VI IS THE NUMBER SIX 6

5 0
3 years ago
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Ashley has a rectangle made out of paper that is 8 cm by12 cm. She folds it in half twice, first vertically and then horizontall
Svetach [21]

Answer:

Area =24cm^2

Step-by-step explanation:

Given

L = 8cm

W = 12cm

r = 2 -- folded twice

Required

The area of the new rectangle

When the length was folder, the new length is:

l = L/2 = 8cm/2 = 4cm

When the width was folder, the new width is:

w = W/2 = 12cm/2 = 6cm

So, the new area is:

Area =l * w

Area =4cm * 6cm

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8 0
3 years ago
Bob bought 8 hockey tickets for $59. Adult tickets cost $10 each and child tickets cost $3 each. How many adult tickets and how
alexdok [17]

Answer:

Bob bought 5 Adult tickets and 3 Child

Step-by-step explanation:

5 adult tickets = 50$

3 Child tickets= 9$

50$+9$= 59$

7 0
3 years ago
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An interior angel of a regular polygon has a measure of 120 degrees. What type of polygon is it
romanna [79]

Answer: The figure is a regular hexagon.

Step-by-step explanation:

8 0
4 years ago
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If the diagonals of a quadrilateral bisect the angles, is the quadrilateral always a parallelogram? Explain your answer.
Liula [17]
Yes. If the diagonals bisect the angles, the quadrilateral is always a parallelogram, specifically, a rhombus.


Consider quadrilateral ABCD. If diagonal AC bisects angles A and C, then ΔACB is congruent to ΔACD (ASA). Hence AB=AD and BC=CD (CPCTC).

Likewise, if diagonal BD bisects angles B and D, triangles BDA and BDC are congruent, thus AB=BC and AD=CD. (CPCTC again). Now, we have AB=BC=CD=AD, so the figure is a rhombus, hence a parallelogram.
6 0
3 years ago
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