The frictional force between the tires and the road prevent the car from skidding off the road due to centripetal force.
If the frictional force is less than the centripetal force, the car will skid when it navigates a circular path.
The diagram below shows that when the car travels at tangential velocity, v, on a circular path with radius, r, the centripetal acceleration of v²/ r acts toward the center of the circle.
The resultant centripetal force is (mv²)/r, which should be balanced by the frictional force of μmg, where μ = coefficient of kinetic friction., and mg is the normal reaction on a car with mass, m.
This principle is applied on racing tracks, where the road is inclined away from the circle to give the car an extra restoring force to overcome the centripetal force.
Answer:
Slope : -1/4
y-intercept : -9
x... 0 , 1
y... -9 , -37/4
Step-by-step explanation: Graph the line using the slope and y-intercept, or two points. GRAPH IS DOWN BELOW!
Hope this helps you out.
You can use the quadratic formula with it which will be easier
or simple factoring
it will be (5x-11)(7x+4)
3x-8=-3+2x
x-8=-3
x=5
the number is 5 hope this helped (:
Answer:
Choice C. The line y =x
Step-by-step explanation:
A function f(x) is symmetric with respect to the y-axis if f(-x) = f(x). If we substitute -x in place of x we end up with a different function. So the function is not symmetric with respect to the y-axis.
Moreover, the function is not symmetric with respect to the x-axis since substituting -y in place of y results into a new function.
If we plot the graph of the function together with the line y =x on the same graph we note that the line y =x acts as a mirror line such that one half of the function lies on the upper end and the other half on the lower end. The function is thus symmetric with respect to the line y =x.
