Answer:
quantity a is halfed
Corrected question;
A quantity a varies inversely as a quantity b, if, when b changes a changes in the inverse ratio. What happens to the quantity a if the quantity b doubles?
Step-by-step explanation:
Analysing the question;
A quantity a varies inversely as a quantity b,
a ∝ 1/b
a = k/b ......1
when b changes a changes in the inverse ratio;
Since the change at the same ratio but inversely, k = 1
So, equation 1 becomes;
a = 1/b
If the quantity b doubles,
ab = 1
a1b1 = a2b2
When b doubles, b2 = 2b1
a1b1 = a2(2b1)
Making a2 the subject of formula;
a2 = a1b1/(2b1)
a2 = a1/2
Therefore, when b doubles, a will be divided by 2, that means a is halfed.
Answer:
2πr or πd
Step-by-step explanation:
Where
π= pi
r= radius of the circle
d= diameter of the circle
The answers 15 because we have two negatives it's always a positive and 3×5 is 15
It is a bit tedious to write 6 equations, but it is a straightforward process to substitute the given point values into the form provided.
For segment ab. (x1, y1) = (1, 1); (x2, y2) = (3, 4).
... x = 1 + t(3-1)
... y = 1 + t(4-1)
ab = {x=1+2t, y=1+3t}
For segment bc. (x1, y1) = (3, 4); (x2, y2) = (1, 7).
... x = 3 + t(1-3)
... y = 4 + t(7-4)
bc = {x=3-2t, y=4+3t}
For segment ca. (x1, y1) = (1, 7); (x2, y2) = (1, 1).
... x = 1 + t(1-1)
... y = 7 + t(1-7)
ca = {x=1, y=7-6t}
