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klio [65]
3 years ago
14

What is the value of the expression? [(1+5)⋅2−5]⋅2

Mathematics
1 answer:
liberstina [14]3 years ago
8 0
USE PEMDAS ( parenthesis, exponents, multiplication, division, addition, subtraction)

[(1+5)⋅2−5]⋅2
[6⋅2−5]⋅2
[12−5]⋅2
7⋅2
14

The answer is: 14
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PLEASE HELP WILL MARK BRAINLIEST The frequency f​ (in waves per​ second) and the wavelength w​ (in meters) of a sound traveling
marshall27 [118]

You gave us the speed and the frequency, and you need the wavelength.

You were also nice enough to remind us that (fqy)x(lng) = speed.

So . . . F x W = 343 m/s

Divide each side by F :

W = (343 m/s) / F

W = (343 m/s) / (240 / s)

W = (343/240) m

<em>W = 1.429 meters</em>

8 0
3 years ago
FIRST CORRECT ANSWER GETS BRAINLIEST!!! 20 POINTS!!!!!
Leto [7]

Answer:

14

Step-by-step explanation:

When you plug this expression into the calc, you should get 14 as your answer.

8 0
3 years ago
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At the amusement park, Laura paid $6.00 for a small cotton candy. Her older brother works at the park, and he told
BabaBlast [244]

Answer:

yes

The price of marked up candy is $6.00

perentage of mark up is 300%

let the marked up amount be represented as x

let 300% mark up be represented as 3x

the equatiopn for finding the price before markup

can be represented as 3x-x=$6.

                                    2x=$6

                                    x=$3.

8 0
3 years ago
Find all values of c in the open interval (a, b) such that f'(c)=(f(b)-f(a))/(b-a)
timama [110]
<h3>Answer:   c = 7/4</h3>

================================================

Work Shown:

Compute the function value at the endpoints

f(x) = \sqrt{4-x}\\\\f(-5) = \sqrt{4-(-5)} = 3\\\\f(4) = \sqrt{4-4} = 0\\\\

With a = -5 and b = 4, we have

f'(c) = \frac{f(b)-f(a)}{b-a}\\\\f'(c) = \frac{f(4)-f(-5)}{4-(-5)}\\\\f'(c) = \frac{0-3}{9}\\\\f'(c) = -\frac{1}{3}\\\\

So,

f(x) = \sqrt{4-x}\\\\f'(x) = -\frac{1}{2\sqrt{4-x}}\\\\f'(c) = -\frac{1}{3}\\\\-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\

Use algebra to solve for c

-\frac{1}{2\sqrt{4-c}} = -\frac{1}{3}\\\\\frac{1}{2\sqrt{4-c}} = \frac{1}{3}\\\\3 = 2\sqrt{4-c}\\\\2\sqrt{4-c} = 3\\\\\sqrt{4-c} = \frac{3}{2}\\\\4-c = \frac{9}{4}\\\\c = 4-\frac{9}{4}\\\\c = \frac{16-9}{4}\\\\c = \frac{7}{4}\\\\

6 0
3 years ago
What is the coefficient of the term 13a in the expression 13a+6b
il63 [147K]

Answer:

The coefficient of the term 13a is, 13

Step-by-step explanation:

Coefficient term are the numbers that multiply the variables or letters

In the given expression: 13a+6b

13a means 13 times a , and a is the variable,

so 13 is the coefficient .

6b means 6 times b , and b is the variable ,

so 6 is the coefficient .

therefore, the coefficient of the term 13a in the given expression is, 13.

5 0
3 years ago
Read 2 more answers
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