Question

Solve by completing the square x^2-6x-4=0

Answer 1

Answer:

x = 3 ± $\sqrt{13}$

Step-by-step explanation:

x² - 6x - 4 = 0 ( add 4 to both sides )

x² - 6x = 4

To complete the square

add ( half the coefficient of the x- term)² to both sides

x² + 2(- 3)x + 9 = 4 + 9

(x - 3)² = 13 ( take square root of both sides )

x - 3 = ± $\sqrt{13}$ ( add 3 to both sides )

x = 3 ± $\sqrt{13}$