2 years ago

Solve by completing the square x^2-6x-4=0

Mathematics

1 answer:

Vesna [10]2 years ago

6 0

Answer:

x = 3 ± $\sqrt{13}$

Step-by-step explanation:

x² - 6x - 4 = 0 ( add 4 to both sides )

x² - 6x = 4

To complete the square

add ( half the coefficient of the x- term)² to both sides

x² + 2(- 3)x + 9 = 4 + 9

(x - 3)² = 13 ( take square root of both sides )

x - 3 = ± $\sqrt{13}$ ( add 3 to both sides )

x = 3 ± $\sqrt{13}$

You might be interested in

5/2x+1/4=12 solve for x

aniked [119]

Answer:

4/5 (2x + 5) − 4 =1

4/5(2x +5) = 1 +4

4/5 (2x +5) = 5

2x + 5 = 5 / (4/5)

2x + 5 = 5 (5/4)

2x + 5 = 25/4

2x = 25/4 - 5

2x = 25/4 - 20/4

2x = 5/4

x = (5/4) / 2

x = (5/4) (1/2)

x = 5/8

x = 0.625

7 0

3 years ago

Read 2 more answers

A right triangle has a side with length 12 in and a hypotenuse with length 20 in. find the length of the missing leg. (round to

OLEGan [10]

Let the unknown side be "z" inches
Through pythagoras:
${12}^{2} + {z}^{2} = {20}^{2}$
Because the square of the two sides add up to the square of the hypotenuse in a right triangle.

This means that
${z }^{2} = {20}^{2} - {12}^{2}$
${z}^{2} = 400 - 144 = 256$
$z = \sqrt{256} = 16$
So the missing side is 16 inches

Hope this helped

6 0

4 years ago

Solve for x. Tx-ux=3t

Veronika [31]

x(t-u) = 3t
dividing both sides by (t-u):
So.. x = 3t/(t-u)

6 0

4 years ago

Graph the system of equations. y = -x + 3 y = -4x -6 NEED HELL ASAP

ololo11 [35]

Idk if this really helps, but I put them into Desmos (free graphing thing) and this popped up