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spin [16.1K]
3 years ago
5

Help me please and thank you​

Mathematics
2 answers:
Klio2033 [76]3 years ago
8 0

Answer:

Quadrant 1!!!

Step-by-step explanation:

snow_lady [41]3 years ago
5 0

Answer:

quadrant 1 should be it

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Contributions to the annual Grayson School fund raising campaign were 10% greater in 1984 than they were in 1983. In 1983, contr
Kobotan [32]

Answer:

6774.075

Step-by-step explanation:

1984: 8855

1983: 8855*10/100=885.5

8855-885.5

7969.5

1982

7969.5*15/100=1195.425

7969.5-1195.425

6774.075

3 0
3 years ago
A: Top 6% of scores B: Scores below the top 6% and above the bottom 59% C: Scores below the top 41% and above the bottom 17% D:
Natalija [7]

Answer:

The numerical limits for a B-grade is between 81 and 92

Step-by-step explanation:

Here in this question, our task is to find the numerical limits for B grade. This means the range between a test taker would be scored a B grade

Please check attachment for complete solution and explanation

3 0
3 years ago
Marcy bought a total of 20 years books and CDs during a yard sale for a total of $54.50 cents. If books cost $1.50 each and CDs
Olenka [21]

Answer:

x + y = 20

1.5x + 5y = 54.50

Solve the equations and get: x = 13 ∧ y = 7

Marcy bought 13 books and 7 CDs.

6 0
4 years ago
Claim: Most adults would erase all of their personal information online if they could.A software firm survey of 453 randomly sel
Anit [1.1K]

Answer:

The value of the test statistic is 4.26.

Step-by-step explanation:

In this case a hypothesis test is performed to determine whether most adults would erase all of their personal information online if they could.

A random sample of <em>n</em> = 453 adults were selected and it was found that 60% of them would erase all of their personal information online if they could.

Assume that the population proportion is, <em>p</em> = 0.50.

A <em>z</em>-test for single proportion would to used to perform the test.

Compute the value of the test statistic as follows:

z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}

  =\frac{0.60-0.50}{\sqrt{\frac{0.50(1-0.50)}{453}}}\\\\=\frac{0.10}{0.0235}\\\\=4.25532\\\\\approx 4.26

Thus, the value of the test statistic is 4.26.

3 0
3 years ago
Helllllppppppp!! Can i have an explanation of this?
Ivahew [28]

Okay so if the regular price of the shirt is 100% as $25 and you have a 30% discount you are still paying 70% (100-30=70) so 70% as a decimal is .70 and $25 x .70 is $17.50. Therefore the shirt is $17.50 after the discount.

6 0
4 years ago
Read 2 more answers
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