Answer:
D is correct. 
Step-by-step explanation:
We are given the root of the equation

If we are given solution of the equation then find equation using formula.
If a and b are the solution of equation then equation would be (x-a)(x-b)=0
Here, 
Equation form would be 
Now we simplify the above equation to get correct option.


So, D is correct. 
There are total of 5 digits, of which we arrange 3 of them.
Therefore using permutations we can find total possible 3-number combinations.
5P3 = 5*4*3 = 60
To be greater than 600 means first digit must be 6. (1 possibility)
A number is even only if last digit is even, 2 or 4. (2 possibilities)
The 2nd digit then can only be 3,5, (2 or 4). (3 possibilities)
The total possible even 3-digit numbers greater than 600 is product of each digit's possibilities.
---> 1*3*2 = 6
Therefore probability is 6/60 = 1/10.
Every 3rd number is even with 2 odd numbers in between successive even numbers.
999/3 = 333 x 2 = 666.
Plug in 6.5 for x.
-8.5x-3.5x=-78
-8.5(6.5)-3.5(6.5)=-78
-55.25-22.75=-78
-78=-78