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vova2212 [387]
3 years ago
6

What is 90 percent as a decimal rounded to the thousandths place (will give brainliest)

Mathematics
1 answer:
Rama09 [41]3 years ago
8 0
Ur answer would be 0.900 please mark me as brainly
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What is 3×584 in expanded form
Ahat [919]
Three mulitplied by five-hundred eighty four

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You are given the right triangle below. Find each of the trig ratios. Enter your answers as fractions in lowest terms.
grin007 [14]

Check this attachment

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The cost in dollars of producing x vehicles for a company is given by C(x)=1200x+5500
GarryVolchara [31]

The rate of change represents the <em>variable production</em> cost rate. The <em>production</em> cost is increased in 1200 units per each <em>additional</em> manufactured car.

<h3>Interpretation of a linear function</h3>

Let be C and x the production cost and the number of vehicles produced, it there is a <em>linear</em> relationship between the two variables, then we have the following formula:

C(x) = \dot r \cdot x + C_{o} (1)

Where:

  • C_{o} - Fixed production costs.
  • \dot r - Variable production cost rate.

In a nutshell, the rate of change represents the <em>variable production</em> cost rate. The <em>production</em> cost is increased in 1200 units per each <em>additional</em> manufactured car. \blacksquare

To learn more on rates of change, we kindly invite to check this verified question: brainly.com/question/8223651

7 0
3 years ago
•<br> Evaluate 15 / (-3) + 5|1-21 / (-5)
katrin [286]

Answer:

20

Step-by-step explanation:

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4 years ago
A random sample of 30 households was selected as part of a study on electricity usage, and the number of kilowatt-hours (kWh) wa
grin007 [14]

Answer:

The 98% confidence interval for the mean usage in the March quarter of 2006, in kWh, was (333.87, 416.13).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 30 - 1 = 29

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 29 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.98}{2} = 0.99. So we have T = 2.462

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.462\frac{91.5}{\sqrt{30}} = 41.13

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 375 - 41.13 = 333.87 kWh

The upper end of the interval is the sample mean added to M. So it is 375 + 41.13 = 416.13 kWh

The 98% confidence interval for the mean usage in the March quarter of 2006, in kWh, was (333.87, 416.13).

6 0
3 years ago
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