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4 years ago

What is the area and perimeter

Mathematics

2 answers:

Lyrx [107]4 years ago

8 0

the area is 12 square meters, and the perimeter is 16.

jek_recluse [69]4 years ago

7 0

Area is 12m amd he perimeter is 12m

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If 4 is added to double the number n, the result is the same as

svlad2 [7]

I think it’s A because 4*2 is 8 and if n were quadrupled it would be 2

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3 years ago

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Un objeto tiene una masa de 120 kg y un volumen de 5 m3. Calcula su densidad y determinada peso específico

AleksandrR [38]

Answer:

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3 years ago

Roby spent two months traveling in country A. The day she arrived, the exchange rate was 1.3 country A dollars per country B. Co

Fantom [35]

Answer:

650 Country A Dollars

Step-by-step explanation:

1 Country B Dollar = 1.3 Country A Dollar

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3 years ago

A new post-surgical treatment is being compared with a standard treatment. Seven subjects receive the new treatment, while seven

a_sh-v [17]

Answer:

$(17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745$

$(17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255$

Step-by-step explanation:

For this case we have the following info given:

Treatment: 12 13 15 19 20 21 24

Control: 18 23 24 30 32 35 39

We can find the sample mean and deviations with the the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s =\sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}$

And repaplacing we got:

$\bar X_T = 17.714$ the sample mean for treatment

$\bar X_C = 28.714$ the sample mean for treatment

$s_T= 4.461$ the sample deviation for treatment

$s_C= 7.387$ the sample deviation for control

$n_T= n_C= 7$ the sample size for each sample

The degrees of freedom are given by:

$df= 7+7-2= 12$

The confidence interval for the difference of means is given by:

$(\bar X_T -\bar X_C) \pm t_{\alpha/2} \sqrt{\frac{s^2_T}{n_T} +\frac{s^2_C}{n_C}}$

The confidence is 98% so then the significance is $\alpha=0.02$ and $\alpha/2 =0.01$ . Then the critical value would be:

$t_{\alpha/2}=2.681$

And replacing we got:

$(17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745$

$(17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255$

4 0

4 years ago

The length of the ladder that will run from the ground to the door of the tree house is nine feet. The plan recommends that the

Gwar [14]

Answer:

13 Rungs

Step-by-step explanation:

According to the Question,

Given, The length of the ladder that will run from the ground to the door of the treehouse is 9 feet ( 9 × 12 = 108 inches).

The plan recommends that the rungs of the ladder be spaced at 8-inch intervals.

And, The first and last rung should be 6 inches from the respective ends.

Thus, the rungs Cover on 108 -(6+6) = 96 inches with 8-inch gaping between each rung.

Therefore, the Total Rungs on the treehouse ladders have (96/8)+1 ⇒ 13 Ladders.

7 0

3 years ago