What is the product of (3x

A 0.1 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selecti

Andrews [41]

Answer:

(a) Null Hypothesis, $H_0$ : p = 0.50

Alternate Hypothesis, $H_A$ : p > 0.50

(b) The value of level of significance (α) given in the question is 0.10.

(c) The sampling distribution of the sample statistic is Normal distribution.

(d) This test is right-tailed.

(e) The value of z test statistics is 0.96.

(f) The P-value is 0.1685.

(g) At 0.10 significance level the z table gives critical value of 1.282 for right-tailed test.

(h) We conclude that the proportion of baby girls is equal to 0.50.

Step-by-step explanation:

We are given that a 0.1 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is greater than 0.5.

Assume that sample data consists of 78 girls in 144 births.

Let p = population proportion of baby girls

(a) So, Null Hypothesis, $H_0$ : p = 0.50 {means that the proportion of baby girls is equal to 0.50}

Alternate Hypothesis, $H_A$ : p > 0.50 {means that the proportion of baby girls is greater than 0.50}

(b) The value of level of significance (α) given in the question is 0.10.

(c) The sampling distribution of the sample statistic is Normal distribution.

(d) This test is right-tailed as in the alternative hypothesis we are concerned for proportion of baby girls that is greater than 0.50.

(e) The test statistics that would be used here One-sample z test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of baby girls = $\frac{78}{144}$ = 0.54

n = sample of births = 144

So, the test statistics = $\frac{0.54-0.50}{\sqrt{\frac{0.54(1-0.54)}{144} } }$

= 0.96

The value of z test statistics is 0.96.

(f) The P-value of the test statistics is given by;

P-value = P(Z > 0.96) = 1 - P(Z < 0.96)

= 1 - 0.8315 = 0.1685

(g) Now, at 0.10 significance level the z table gives critical value of 1.282 for right-tailed test.

(h) Since our test statistic is less than the critical value of z as 0.96 < 1.282, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region (which was to the right of value of 1.282) due to which we fail to reject our null hypothesis.

Therefore, we conclude that the proportion of baby girls is equal to 0.50.

7 0

3 years ago

2.3. Use the following subtraction strategies to calculate 884-597: 2.3.1. breaking up the second number 2.3.2. adding on to the

DochEvi [55]

It should be noted that the value of 597 subtracted from 884 is 287.

<h3>How to illustrate the subtraction?</h3>

The information is simply that we should subtract 884 and 597 and also illustrate it.

This will be:

884 - 597 = 287.

A word problem illustrating this is that a man had 884 pens and gave 597 pens to his friends. How many pens does he have left?

This will be:

= 884 - 597 = 287

Learn more about subtraction on:

brainly.com/question/220101

#SPJ1

4 0

2 years ago

Lana has a ribbon that is 2.2 meters long. She cuts the ribbon into 4 equal pieces to trim the edges of her bulletin board. What

stepan [7]

i think that it is 2.2\4=0.55

7 0

3 years ago

Teresa purchased a prepaid phone card for $20. Long distance calls cost 16 cents a minute using this card. Teresa used her card

shtirl [24]

Answer:

33 minutes. 20- 14.72=5.28

Step-by-step explanation:

20- 14.72=5.28. then divide 5.28 by .16(cents per minute) to get 33 minutes

8 0

3 years ago

Consider the probability that no fewer than 74 out of 112 houses will lose power once a year. Assume the probability that a give

Natasha_Volkova [10]

Answer: the normal curve can be used as an approximation to the binomial probability considering the following condition: when the sample is large, in this case n=112

Step-by-step explanation:

for a binomial experiment to be approximated to normal distribution, the following conditions must be present:

i. sample size must be large, in this case sample size is 112

ii. the mean must be equal to np,where n is sample size and p is probability of success

iii. the standard deviation must be equal to npq,where q is the probability of failure

5 0

3 years ago

What is the product of (3x - 2)(2x^2 + 5)?