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Karolina [17]
3 years ago
7

Please explain how to do this and show work

Mathematics
1 answer:
Sati [7]3 years ago
3 0
Something u need to do dude
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Evaluate -6 minus parentheses -1 parentheses
GREYUIT [131]
-6 minus parentheses -1 parentheses

-6 - (-1)
When there are two negatives, they cancel out to create a positive.

-6 + 1

The answer is -5.
6 0
3 years ago
The entire question is un the picture
n200080 [17]
A) 6x -5y = 5
B) 3x + 5y = 4
Adding the equations:
9x = 9
x = 1

A) 6*1 -5y = 5
A) 6 - 5 = 5y
A) 5y = 1
y = 1/5 = .2


7 0
2 years ago
How do you determine if a relation is quadratic by calculation differences, analyzing a graph, examining the degree in an equati
Kryger [21]

1) We can determine by the table of values whether a function is a quadratic one by considering this example:

x | y 1st difference 2nd difference

0 0 3 -0 = 3 7-3 = 4

1 3 10 -3 = 7 11 -7 = 4

2 10 21 -10 =11 15 -11 = 4

3 21 36-21 = 15 19-5 = 4

4 36 55-36= 19

5 55

2) Let's subtract the values of y this way:

3 -0 = 3

10 -3 = 7

21 -10 = 11

36 -21 = 15

55 -36 = 19

Now let's subtract the differences we've just found:

7 -3 = 4

11-7 = 4

15-11 = 4

19-15 = 4

So, if the "second difference" is constant (same result) then it means we have a quadratic function just by analyzing the table.

3) Hence, we can determine if this is a quadratic relation calculating the second difference of the y-values if the second difference yields the same value. The graph must be a parabola and the highest coefficient must be 2

4 0
9 months ago
Using the law of cosines, a=_ rounded to the nearest tenth.
Leya [2.2K]
A^2 = 4.0^2 + 3.7^3 - 2*4*3.7 cos 334

= 4.865

a =  2.2  to nearest tenth.
5 0
3 years ago
Read 2 more answers
Need help please. don’t know it
Ahat [919]
I believe more likely a. :)
7 0
2 years ago
Read 2 more answers
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