-6 minus parentheses -1 parentheses
-6 - (-1)
When there are two negatives, they cancel out to create a positive.
-6 + 1
The answer is -5.
A) 6x -5y = 5
B) 3x + 5y = 4
Adding the equations:
9x = 9
x = 1
A) 6*1 -5y = 5
A) 6 - 5 = 5y
A) 5y = 1
y = 1/5 = .2
1) We can determine by the table of values whether a function is a quadratic one by considering this example:
x | y 1st difference 2nd difference
0 0 3 -0 = 3 7-3 = 4
1 3 10 -3 = 7 11 -7 = 4
2 10 21 -10 =11 15 -11 = 4
3 21 36-21 = 15 19-5 = 4
4 36 55-36= 19
5 55
2) Let's subtract the values of y this way:
3 -0 = 3
10 -3 = 7
21 -10 = 11
36 -21 = 15
55 -36 = 19
Now let's subtract the differences we've just found:
7 -3 = 4
11-7 = 4
15-11 = 4
19-15 = 4
So, if the "second difference" is constant (same result) then it means we have a quadratic function just by analyzing the table.
3) Hence, we can determine if this is a quadratic relation calculating the second difference of the y-values if the second difference yields the same value. The graph must be a parabola and the highest coefficient must be 2
A^2 = 4.0^2 + 3.7^3 - 2*4*3.7 cos 334
= 4.865
a = 2.2 to nearest tenth.
I believe more likely a. :)
