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2 years ago

How many 1 1/2 liter bottles of water does it take to fill a 16 liter jug? show work

Mathematics

1 answer:

Ghella [55]2 years ago

7 0

Answer: 11 bottles approximately.

Step-by-step explanation:

The first step you can apply in order to solve this exercise, is to convert the mixed number to a decimal number. The procedure to this is:

1. Divide the numerator 1 by the denominator 2.

2. Add the quotient obtained to the whole number part.

Then, this is:

$1\frac{1}{2} =1+\frac{1}{2}=1+0.5=1.5$

According to the information provided in the exercise, a jug of 16 liters must be filled using bottles of 1.5 liters of water.

So, let be "x" the amount of 1.5 liters bottles of water that takes the fill the jug of 16 liters.

To find the value of "x", you need to divide 16 liters by 1.5 liters. Then:

$\frac{16\ liters}{1.5}=10.6\approx11$

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2 years ago

Three times a number n plus 16

HACTEHA [7]

Answer:

3n+16

Step-by-step explanation:

three times: (3) a number n +16

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3 years ago

C= m over 3 π d to the second power , for m

julia-pushkina [17]

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2 years ago

Let alpha and beta be conjugate complex numbers such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}

miskamm [114]

Answer:

$-3+i\sqrt{3} , 1+\sqrt{3}$

Step-by-step explanation:

Given that alpha and beta be conjugate complex numbers

such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}.

Let

$\alpha = x+iy\\\beta = x-iy$

since they are conjugates

$\alpha-\beta = x+iy-(x-iy)\\= 2iy= 2i\sqrt{3} \\y =\sqrt{3}$

$\frac{\alpha}{\beta^2} }\\=\frac{x+i\sqrt{3} }{(x-i\sqrt{3})^2} \\=\frac{x+i\sqrt{3}}{x^2-3-2i\sqrt{3}} \\=\frac{x+i\sqrt{3}((x^2-3+2i\sqrt{3}) }{(x^2-3-2i\sqrt{3)}(x^2-3-2i\sqrt{3})}$

Imaginary part of the above =0

i.e. $\sqrt{3} (x^2-3)+2x\sqrt{3} =0\\x^2+2x-3=0\\(x+3)(x-1) =0\\x=-3,1$

So the value of alpha = $-3+i\sqrt{3} , 1+\sqrt{3}$

3 0

2 years ago

Solve for x. <br><br> Brainlest for anyone who helps!! <br><br> thanks you

gavmur [86]

<h3>Answer: C) 0</h3>

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Explanation:

If points F and E are the midpoints of segment VU and segment ST respectively, then segment FE is the midsegment of the trapezoid. The midsegment is parallel to the bases, and the midsegment's length is found by adding up the bases VS and UT, then dividing by 2.

(VS + UT)/2 = FE

(29 + x+17)/2 = 23 ... plug in given info; isolate x

(x+46)/2 = 23

x+46 = 23*2 ... multiply both sides by 2

x+46 = 46

x = 46-46 ... subtract 46 from both sides

6 0

3 years ago

How many 1 1/2 liter bottles of water does it take to fill a 16 liter jug? show work​

How many 1 1/2 liter bottles of water does it take to fill a 16 liter jug? show work