All categories

3 years ago

How many 1 1/2 liter bottles of water does it take to fill a 16 liter jug? show work

Mathematics

1 answer:

Ghella [55]3 years ago

7 0

Answer: 11 bottles approximately.

Step-by-step explanation:

The first step you can apply in order to solve this exercise, is to convert the mixed number to a decimal number. The procedure to this is:

1. Divide the numerator 1 by the denominator 2.

2. Add the quotient obtained to the whole number part.

Then, this is:

$1\frac{1}{2} =1+\frac{1}{2}=1+0.5=1.5$

According to the information provided in the exercise, a jug of 16 liters must be filled using bottles of 1.5 liters of water.

So, let be "x" the amount of 1.5 liters bottles of water that takes the fill the jug of 16 liters.

To find the value of "x", you need to divide 16 liters by 1.5 liters. Then:

$\frac{16\ liters}{1.5}=10.6\approx11$

You might be interested in

If 20 is decreased to 18.6, the decrease is what percent of the original number?

Lady bird [3.3K]

Answer:

1.4

Step-by-step explanation:

10 decreased by 1.4 is 18.6

5 0

3 years ago

The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)

Lemur [1.5K]

Answer:

Cardiac output: $F=0.055 L\s$

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output: $F=\frac{A}{\int\limits^T_0 {c(t)} \, dt}$ ---1

A = 3 mg

$\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt$

Do, integration by parts

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}$

Substitute the value in 1

Cardiac output: $F=\frac{3}{54.49}$

Cardiac output: $F=0.055 L\s$

Hence Cardiac output: $F=0.055 L\s$

4 0

3 years ago

Combine the like terms to create an equivalent expression −n+(−3)+3n+5

spin [16.1K]

Answer:

2n+2

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Pls help help with this problem it's big hard thx

dimulka [17.4K]

It's asking for the coordinates of the treasure and I can't really see it right but it looks like the coordinate is about (-0.5, 1.5) it's not exact though cuz I can't really see it

8 0

3 years ago

Find three numbers such that their sum is 12, the sum of the first, twice the second, and three times the third is 31, and the s

Tpy6a [65]

Answer:

a = 3, b = -1, c = 10

Step-by-step explanation:

Let the three numbers be a, b and c.

Equation 1: a + b + c = 12

Equation 2: a + 2b + 3c = 31

Equation 3: 9b + c = 1

Equation 2 - Equation 1:

Equation 4: b + 2c = 19

Equation 3 times by the number 2

Equation 5: 18b + 2c = 2

Equation 5 - Equation 4

17b = -17

b = -1

Substitute into Equation 4:

2c - 1 = 19

2c = 20

c = 10

Substitute into Equation 1:

a + b + c = 12

a - 1 + 10 = 12

a = 3

8 0

2 years ago

Read 2 more answers

How many 1 1/2 liter bottles of water does it take to fill a 16 liter jug? show work​

How many 1 1/2 liter bottles of water does it take to fill a 16 liter jug? show work