Answer:
B
(x+4)(x2−8x+3)
=(x+4)(x2+−8x+3)
=(x)(x2)+(x)(−8x)+(x)(3)+(4)(x2)+(4)(−8x)+(4)(3)
=x3−8x2+3x+4x2−32x+12
=x3−4x2−29x+12
Answer:
184.85 square mm
Step-by-step explanation:
The area of a sector of a circle is
, where r is the radius and
is the angle in radians subtended by the arc at the centre of the circle.
Since, diameter = 40.6 mm
So, radius(r)=20.3 mm and
=
radians
So, area of sector= 
=
=184.85 square mm
1. let x = a number
x^2+5
2. let x = a number
2x-(x+19)
3. let x = a number
2x=1/3x + 9
4. let x = 1st integer
x+1 = 2nd integer
x+2 = 3rd integer
(x+x+1+x+2)/4
=(3x+3)/4
5. let x=smallest integer
x+1 = 2nd integer
x+2 = 3rd integer
x+3 = largest integer
x+x+1+x+2+x+3 = 9(x+3)
= 4x+6= 9x+27
Answer:
its 3/5 so you just add the numerator to the numerator and add the denominator to the denominator.