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rewona [7]
2 years ago
8

A casserole recipe calls for 4 ounces of cheese. Adrian wants to use 1/2 of the amount of cheese in his casseroles. How many pou

nds of cheese does he need to make 28 casseroles with his revised recipe?
Mathematics
1 answer:
denis-greek [22]2 years ago
3 0

Answer:

She will need 3.5 pounds of cheese to make the 28 casseroles

Step-by-step explanation:

In this question, we are tasked with calculating the amount of cheese in pounds needed to make 28 casseroles.

In the revised recipe, she intends using 1/2 of what is supposed to be used in the original recipe. Mathematically, since each original casseroles is meant to take 4 ounces of cheese, the revised recipe taking half will have 1/2 × 4 = 2 ounces of cheese per casserole

Now for 28 casseroles based on the revised recipe, the total amount of cheese to be used mathematically is equal to 28 × 2 = 56 ounces of casserole

The questions asks that our answer be in pounds

Mathematically, 1 ounce = 0.0625 pounds

Hence, 56 ounces of casseroles will be 56 × 0.0625 = 3.5 pounds of cheese

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C is a non terminating decimal.

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b = 0.8

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The heights of 200 adults were recorded and divided into two categories.
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german

The equation of the parabola that similar to f(x) = 7x^2 but the vertex is (3, 5) in the standard form is y = 7(x-3)^2 + 5

The equation of the parabola

f(x) = 7x^2

The standard vertex form of a parabola is

y = a(x-h)^2 + k

The coordinates of the vertex of a parabola = (3, 5)

Where (h, k)  is the coordinates

From the given function of the parabola f(x) =  7x^2

The value of a = 7

Substitute the values in the vertex form of a parabola

y = 7(x-3)^2 + 5

Hence, the equation of the parabola that is similar to f(x) = 7x^2 but the vertex is (3, 5) in the standard form is y = 7(x-3)^2 + 5

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3 0
1 year ago
The Reviews editor for a certain scientific journal decides whether the review for any particular book should be short (1–2 page
Pavlova-9 [17]

Answer:

The probability that the selected review was submitted in Word format is 0.56.

Step-by-step explanation:

We are given that Data on recent reviews indicates that 50% of them are short, 30% are medium, and the other 20% are long. Reviews are submitted in either Word or LaTeX. For short reviews, 70% are in Word, whereas 50% of medium reviews are in Word and 30% of long reviews are in Word.

Let the probability that there are short reviews = P(S) = 0.50

The probability that there are medium reviews = P(M) = 0.30

The probability that there are long reviews = P(L) = 0.20

Let W = event that the reviews are submitted in either Word or LaTeX

So, the probability that short reviews are submitted in Word = P(W/S) = 0.70

The probability that medium reviews are submitted in Word = P(W/M) = 0.50

The probability that long reviews are submitted in Word = P(W/L) = 0.30

(a) The probability that the selected review was submitted in Word format is given by = P(W)

    P(W) = P(S) \times P(W/S) + P(M) \times P(W/M) + P(L) \times P(W/L)  

             = (0.50 \times 0.70) + (0.30 \times 0.50) + (0.20 \times 0.30)

             = 0.35 + 0.15 + 0.06

             = 0.56

Hence, the probability that the selected review was submitted in Word format is 0.56.

(b) Now, if the selected review was submitted in Word format, the posterior probabilities of it being short is given by = P(S/W)

        P(S/W) = \frac{P(S) \times P(W/S)}{P(S) \times P(W/S)+P(M) \times P(W/M)+P(L) \times P(W/L)}

                    = \frac{0.50\times 0.70}{0.50\times 0.70+0.30\times 0.50+0.20\times 0.30}

                    = \frac{0.35}{0.56} = <u>0.625</u>

Similarly, if the selected review was submitted in Word format, the posterior probabilities of it being medium is given by = P(M/W)

        P(M/W) = \frac{P(M) \times P(W/M)}{P(S) \times P(W/S)+P(M) \times P(W/M)+P(L) \times P(W/L)}

                     = \frac{0.30\times 0.50}{0.50\times 0.70+0.30\times 0.50+0.20\times 0.30}

                     = \frac{0.15}{0.56} = <u>0.268</u>

Also, if the selected review was submitted in Word format, the posterior probabilities of it being long is given by = P(L/W)

        P(L/W) = \frac{P(L) \times P(W/L)}{P(S) \times P(W/S)+P(M) \times P(W/M)+P(L) \times P(W/L)}

                     = \frac{0.20\times 0.30}{0.50\times 0.70+0.30\times 0.50+0.20\times 0.30}

                     = \frac{0.06}{0.56} = <u>0.107.</u>

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2 years ago
What is the constant of variation for the quadratic variation?
Lorico [155]
Given:
x  =   2     3     4      5     6
y  = 20 ; 45 ; 80; 125;180

The constant variation for the quadratic variation is 5.

y = 5x²
y = 5(2²) = 5(4) = 20
y = 5(3²) = 5(9) = 45
y = 5(4²) = 5(16) = 80
y = 5(5²) = 5(25) = 125
y = 5(6²) = 5(36) = 180
7 0
3 years ago
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