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rewona [7]
3 years ago
8

A casserole recipe calls for 4 ounces of cheese. Adrian wants to use 1/2 of the amount of cheese in his casseroles. How many pou

nds of cheese does he need to make 28 casseroles with his revised recipe?
Mathematics
1 answer:
denis-greek [22]3 years ago
3 0

Answer:

She will need 3.5 pounds of cheese to make the 28 casseroles

Step-by-step explanation:

In this question, we are tasked with calculating the amount of cheese in pounds needed to make 28 casseroles.

In the revised recipe, she intends using 1/2 of what is supposed to be used in the original recipe. Mathematically, since each original casseroles is meant to take 4 ounces of cheese, the revised recipe taking half will have 1/2 × 4 = 2 ounces of cheese per casserole

Now for 28 casseroles based on the revised recipe, the total amount of cheese to be used mathematically is equal to 28 × 2 = 56 ounces of casserole

The questions asks that our answer be in pounds

Mathematically, 1 ounce = 0.0625 pounds

Hence, 56 ounces of casseroles will be 56 × 0.0625 = 3.5 pounds of cheese

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Answer:

2/9

Step-by-step explanation:

If you meant you want to find U,

1) Divide both side by 2. -> U = 4/9 divided by 2

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two mountain bikers leave from the same parking lot and head in opposite directions on two different trails. the first rider goe
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Applying the required <em>rule </em>or <em>theorem</em>, it can be concluded that the second biker is <u>farther</u> from the <em>parking lot</em>. The distance of the bikers to the <em>parking lot</em> are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The <u>path</u> of travel of both bikers would form a triangle. Applying the <u>Pythagoras</u> theorem to the path of the <em>first</em> biker would give his <u>distance</u> from the starting point. While applying the <u>cosine</u> rule to the path of <em>second</em> rider would gives his <u>distance</u> to the starting point.

Thus,

a. <u>To determine the distance of the first biker from the parking lot.</u>

Let the required <em>distance </em>be represented by x. Applying the Pythagoras theorem, we have:

hyp^{2} = adj 1^{2} + adj 2^{2}

x^{2} = 8^{2} + 15^{2}

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x = \sqrt{289}

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x = 17 km

Thus, the <u>first</u> biker is 17.0 km from the <em>starting</em> point.

b. <u>To determine the distance of the second biker from the parking lot.</u>

Let the required <em>distance</em> be represented by x. So that applying the cosine rule, we have:

c^{2} = a^{2} + b^{2} - 2ab Cos θ

x^{2} = 8^{2} + 15^{2} - 2(15*8) Cos (180 - 20)

    = 64 + 225 - 240 Cos 160

    = 289 - 240 * -0.5

x^{2} = 289 + 120

   = 409

x = \sqrt{409}

 = 20.2237

x = 20.22 km

Thus, the <u>second</u> biker is 20.22 km from the <em>starting</em> point.

Therefore, the second biker is <u>farther</u> from the <em>parking lot</em>.

A sketch of the path of travel for the two bikers is attached for more clarifications.

Visit: brainly.com/question/22699651

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igor_vitrenko [27]

Answer:

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