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Gennadij [26K]
3 years ago
14

please look at the problem and help. I tried to ask my teacher for help earlier but she ignored me so please don't ignore this.

:c

Mathematics
1 answer:
Alchen [17]3 years ago
8 0
36*40+36*40-6*6=2844ft^2

we had to subtract the area of the closet so it wasn't counted twice :P
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Mx+nx=p solve for x please
Irina-Kira [14]
X(m+n) = p
x = p/(m+n)

Hope this helps!
5 0
3 years ago
I need help with my math homework. The questions is: Find all solutions of the equation in the interval [0,2π).
Aleksandr-060686 [28]

Answer:

\frac{7\pi}{24} and \frac{31\pi}{24}

Step-by-step explanation:

\sqrt{3} \tan(x-\frac{\pi}{8})-1=0

Let's first isolate the trig function.

Add 1 one on both sides:

\sqrt{3} \tan(x-\frac{\pi}{8})=1

Divide both sides by \sqrt{3}:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}

Now recall \tan(u)=\frac{\sin(u)}{\cos(u)}.

\frac{1}{\sqrt{3}}=\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}

or

\frac{1}{\sqrt{3}}=\frac{-\frac{1}{2}}{-\frac{\sqrt{3}}{2}}

The first ratio I have can be found using \frac{\pi}{6} in the first rotation of the unit circle.

The second ratio I have can be found using \frac{7\pi}{6} you can see this is on the same line as the \frac{\pi}{6} so you could write \frac{7\pi}{6} as \frac{\pi}{6}+\pi.

So this means the following:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}

is true when x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi

where n is integer.

Integers are the set containing {..,-3,-2,-1,0,1,2,3,...}.

So now we have a linear equation to solve:

x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi

Add \frac{\pi}{8} on both sides:

x=\frac{\pi}{6}+\frac{\pi}{8}+n \pi

Find common denominator between the first two terms on the right.

That is 24.

x=\frac{4\pi}{24}+\frac{3\pi}{24}+n \pi

x=\frac{7\pi}{24}+n \pi (So this is for all the solutions.)

Now I just notice that it said find all the solutions in the interval [0,2\pi).

So if \sqrt{3} \tan(x-\frac{\pi}{8})-1=0 and we let u=x-\frac{\pi}{8}, then solving for x gives us:

u+\frac{\pi}{8}=x ( I just added \frac{\pi}{8} on both sides.)

So recall 0\le x.

Then 0 \le u+\frac{\pi}{8}.

Subtract \frac{\pi}{8} on both sides:

-\frac{\pi}{8}\le u

Simplify:

-\frac{\pi}{8}\le u

-\frac{\pi}{8}\le u

So we want to find solutions to:

\tan(u)=\frac{1}{\sqrt{3}} with the condition:

-\frac{\pi}{8}\le u

That's just at \frac{\pi}{6} and \frac{7\pi}{6}

So now adding \frac{\pi}{8} to both gives us the solutions to:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}} in the interval:

0\le x.

The solutions we are looking for are:

\frac{\pi}{6}+\frac{\pi}{8} and \frac{7\pi}{6}+\frac{\pi}{8}

Let's simplifying:

(\frac{1}{6}+\frac{1}{8})\pi and (\frac{7}{6}+\frac{1}{8})\pi

\frac{7}{24}\pi and \frac{31}{24}\pi

\frac{7\pi}{24} and \frac{31\pi}{24}

5 0
3 years ago
What is an equation of the line that passes through the point (4, -1) and has
Nuetrik [128]

Answer:

y + 1 = -5(x - 4)

y + 1 = -5x + 20

y = -5x + 19

8 0
3 years ago
X + 6y = 2 4x - 3y = 10 Pick the first step to solving this system of equations using the addition method.
podryga [215]
<span>This one is the correct answer----->Multiply the bottom equation by 2 thus eliminating the y variable when the equations are added together.

</span><span>X + 6y = 2 ....top
</span><span>4x - 3y = 10...bottom

if we multiply the bottom equation by 2 .......... =>  8x - 6y = 20
if we add it to the top one..........>(8+1)x +(6-6)y = (20+2)
then we solve for x =>   x = 22/9 

then with the top equation, we solve for y == >  y = -2/27</span>
4 0
3 years ago
23. If 25% of a number is 75. find the number.<br>A. 700 B. 600 C. 500 D, 400 E. 300​
nadya68 [22]

Answer:

<em><u>2</u></em><em><u>3</u></em><em><u>.</u></em><em><u>E</u></em>

Step-by-step explanation:

<em><u>please click the heart and rate excellent and brainleist to </u></em><em><u>☻</u></em><em><u>❤</u></em><em><u>☺️</u></em><em><u>☺️</u></em><em><u>❤</u></em><em><u>☻</u></em>

4 0
3 years ago
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