Answer:
11 months
Step-by-step explanation:
185 - 20 = 165
165 ÷ 15 = 11
 
        
             
        
        
        
Remark
There is no short way to do this problem and no obvious way to get the answer other that to solve each part.   
Solve
A
 Multiply by 2
                    Multiply by 2
x + 1.6 = 2(x + 0.1)                                         Remove the brackets
x + 1.6 = 2x + 0.1*2                                        
x + 1.6 = 2x + 0.2                                          Subtract x from both sides
1.6 = x + 0.2                                                  Subtract 0.2 from both sides   
1.6 - 0.2 = x                         
1.4 = x
Circle A
B
Subtract 2x from both sides.
3x - 2x = 1.4
Circle B
C
Remove the brackets.
4x + 6 = 2x - 6           Add 6 to both sides
4x + 12 = 2x               Subtract 4x from both sides.
12 = -2x                      Divide by - 2
12/-2 = x
x = - 6                         Don't circle C
D
I'm going to be very scant in my solution of this. You can fill in the steps.
3x = 4.2
x = 4.2/3
x = 1.4
Circle D
 
        
                    
             
        
        
        
Answer:
(A)  
Step-by-step explanation:
From the given figure, we have to prove whether the two given triangles are congruent or similar.
Thus, From the figure, ∠3=∠4 (Vertically opposite angles)
Since, KL and NO are parallel lines and KO and LN are transversals, then 
measure angle 1= measure angle 5 that is ∠1=∠5(Alternate angles).
Thus, by AA similarity rule, ΔKLM is similar to ΔONM.
Thus, Option A that is Triangle KLM is similar to triangle ONM because measure of angle 3 equals measure of angle 4 and measure of angle 1 equals measure of angle 5 is correct.
 
        
                    
             
        
        
        
Answer:
<7=120
<8=60
Step-by-step explanation:
<2 and <7 are alternate exterior angles. <7 and <8 are complementary sor just do 180-120 and you will get 60
 
        
             
        
        
        
25 cubic inches because you know that every cone is a third of the volume of the cylinder with which it shares a height and base with.