What is the equation describing the position of particle b?
1 answer:
<span>Let us suppose that two particles A and B start moving. Particle A starts moving at time t = 0 and velocity v. At time t, particle B has twice acceleration, half velocity and same position as the particle A has at time t=0. </span>
So, position of particle B depends on time
<span>The equation of motion can be written as:</span>
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Answer:
n=21
Step-by-step explanation:
We must find n.
Remember PEMDAS. First we must do the Parentheses. Lets do distributive property by multiplying a number that is immediately outside the parentheses with each number inside the parentheses. Lets do this one side at a time.
First lets do 5(n - 7). We get 5n - 35
Now 2(n + 14) is 2n + 28
Okay...... now we have
Now lets do OPPOSITES!!!! We must do the opposite of each thing to both sides.
The opposite of -35 is positive 35. Lets add 35 to both sides. We get:
Now lets do the opposite of 2n which is -2n
this is looking quite nice isnt it..........
The opposite of 3 times n is 3 DIVIDED BY n. So lets divide both sides by 3
amazing.......
Answer:
see explanation
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
here m = - , hence
y = - x + c ← is the partial equation
To find c substitute (- 3, - 1) into the partial equation
- 1 = 2 + c ⇒ c = - 1 - 2 = - 3
y = - x - 3 ← is the equation of the line