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3 years ago

10

During WW2, mortars were fired from trenches dug 4 feet in the ground. The mortars had an average velocity of 150 ft/s. What is

the highest altitude the mortar can reach, and how long would it take to strike its target?

1 answer:

san4es73 [151]3 years ago

5 0

uh...probably not very long

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Given below are lease terms at the local dealership. What is the total

ivolga24 [154]

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2. Monthly payments : $425.00

3. Security deposit: $375.00

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Step-by-step explanation:

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3 years ago

Find the value of the variable.

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3 years ago

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3 years ago

Read 2 more answers

Find the max/min value of f(x) = 2x2 + 3x - 5

Lelechka [254]

Answer:

The minimum value is $(-\frac{3}{4},-\frac{49}{8})$ or $(-0.75,-6.125)$

Step-by-step explanation:

we have

$f(x)=2x^{2}+3x-5$

This is the equation a vertical parabola open upward

The vertex represent a minimum

The general equation in vertex form is

$f(x)=a(x-h)^2+k$

where

(h,k) is the vertex

Convert the given function in vertex form

$f(x)=2x^{2}+3x-5$

Factor 2

$f(x)=2(x^{2}+\frac{3}{2}x)-5$

Complete the square

$f(x)=2(x^{2}+\frac{3}{2}x+\frac{9}{16})-5-\frac{9}{8}$

$f(x)=2(x^{2}+\frac{3}{2}x+\frac{9}{16})-\frac{49}{8}$

Rewrite as perfect squares

$f(x)=2(x+\frac{3}{4})^{2}-\frac{49}{8}$

The vertex is the point $(-\frac{3}{4},-\frac{49}{8})$

8 0

3 years ago

If someone could help u would be amazing!!!!!

GaryK [48]

Tasha's mistake is in Step 4
she has a negative sign in front of the fraction and she has a negative exponent on the 4 in the denominator

3 0

3 years ago