Degree of ploynominal is the largest exponent you find, which is here the 4x to the 6th. there are only two terms here.
Answer:
11 is the median of the entire data set
6 is the median of the lower half and 16 is the median of the upper half data scores...
Subtract 16 from 6 gives 10 so the answer is C) 10
In your question where ask to find the Standard Normal Distribution of the following:
give probabilities for 0<Z<infinity.
For these ranges, you can read directly, for example,
P(Z<1.96)=0.975.
So for #1, you read directly on the line 1.3 and column 0.03.
For #2, we note that the distribution is symmetrical about Z=0, so
P(Z<-2.33) is the same as P(Z>2.33)
which again is the same as
1-P(Z<2.33) because we know that the area under a probability distribution function adds up to 1.
For the remaining questions, work is similar to #2.
<h2><u>
Answer with explanation</u>
:</h2>
Let
be the population mean.
As per given , we have

Since the alternative hypothesis is right-tailed , so the test is a right-tailed test.
Also, population standard deviation is given
, so we perform one-tailed z-test.
Test statistic : 
, where
= Population mean
= Population standard deviation
n= sample size
= Sample mean
For n= 18 ,
,
,
, we have

P-value (for right tailed test): P(z>2.12) = 1-P(z≤ 2.12) [∵ P(Z>z)=1-P(Z≤z)]\
=1- 0.0340=0.9660
Decision : Since P-value(0.9660) > Significance level (0.01), it means we are failed to reject the null hypothesis.
[We reject null hypothesis if p-value is larger than the significance level . ]
Conclusion : We do not have sufficient evidence to show that the goal is not being met at α = .01 .
Answer:
y=6
Step-by-step explanation:
edge2020