In a school election, Juan received 4 times as many votes as Wayne, Neal recurved twenty less votes than Juan, and Kerry got hal
1 answer:
Votes received by Wayne is 112
<em><u>Solution:</u></em>
To find: votes received by Wayne
Let the vote received by Wayne be "x"
<em><u>Juan received 4 times as many votes as Wayne</u></em>
Therefore,
Juan votes = 4 times as many votes as Wayne
Juan votes = 4x ---- eqn 1
<em><u>Neal received twenty less votes than Juan</u></em>
Neal votes = twenty less votes than Juan
Neal votes = Juan votes - 20
Neal votes = 4x - 20 ---- eqn 2
<em><u>Kerry got half as many votes as Neal</u></em>
Kerry votes = half of neal votes
Kerry votes = ---- eqn 3
The total votes cast in the election was 1,202
Wayne votes + Juan votes + Neal votes + Kerry votes = 1202
Plug in eqn 1 , eqn 2, eqn 3
Therefore votes received by Wayne is 112
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Answer:
Step-by-step explanation:
This is a conditional probability exercise.
Let's name the events :
I : ''A person is infected''
NI : ''A person is not infected''
PT : ''The test is positive''
NT : ''The test is negative''
The conditional probability equation is :
Given two events A and B :
P(A/B) = P(A ∩ B) / P(B)
P(A/B) is the probability of the event A given that the event B happened
P(A ∩ B) is the probability of the event (A ∩ B)
(A ∩ B) is the event where A and B happened at the same time
In the exercise :
We are looking for P(I/PT) :
P(I/PT)=P(I∩ PT)/ P(PT)
P(PT/I)=P(PT∩ I)/P(I)
0.904=P(PT∩ I)/0.025
P(PT∩ I)=0.904 x 0.025
P(PT∩ I) = 0.0226
P(PT/NI)=0.041
P(PT/NI)=P(PT∩ NI)/P(NI)
0.041=P(PT∩ NI)/0.975
P(PT∩ NI) = 0.041 x 0.975
P(PT∩ NI) = 0.039975
P(PT) = P(PT∩ I)+P(PT∩ NI)
P(PT)= 0.0226 + 0.039975
P(PT) = 0.062575
P(I/PT) = P(PT∩I)/P(PT)
Answer: 60%
Step-by-step explanation:
Since, According to the question, Last quarter, we successfully completed an average of about 5 chemical analyses per day.
Therefore initially our average = 5 chemical analyses per day.
Again, From the question, This quarter, we have increased this average to about 8 per day.
Therefore New average =chemical analyses 8 per day
Thus, Percentage change in the average = (Initial average - New average)×100/ initial average
=
=
= 60 %
Therefore, Percentage change in the average=60 %