Angle m∠8 =41° and x=10°
Step-by-step explanation:
Given that m∠3=139° then
m∠3=m∠1 = corresponding angles = 139° and m∠7=m∠5=m∠3=139°
m∠8= 180°-139° =41° -sum of angles on a straight line
m∠8=m∠6=m∠4=m∠2= 41°
2.
Given that m∠3=8x+70° and m∠8=4x-10° then you can find the value of x as;
m∠3+m∠8=180°
8x+70°+4x-10°=180°
12x+60°=180°
12x=180°-60°
12x=120°
12x/12 =120°/12
x=10°
Hence,
m∠3=8x+70° = 8*10 +70° = 80°+70°=150°
m∠8= 4x-10° = 4*10 - 10° = 40°-10° =30°
m∠1 =m∠3 = m∠5 = m∠7 =150°
m∠2 = m∠ 4 = m∠6 = m∠8 =30°
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Angles : brainly.com/question/12157314
Keywords : parallel lines, transversal, angles
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