27 as a mixed number
1 answer:
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Answer:
<u> x = 16</u>
Step-by-step explanation:
See the attched figure
We should know that, one of the properties of the rhombus is the diagonals bisect the angles of the rhombus.
Given:
m∠ABC = 84 and m∠ABE = 3x − 6
So, m∠ABE = 0.5 * m∠ABC = 0.5 * 84 = 42
∴ 3x - 6 = 42
Solve for x
3x = 42 + 6 = 48
x = 48/3 = 16
<u>∴ x = 16</u>
Answer:
Gila Monster is 1.54 times that of Chuckwalla.
Step-by-step explanation:
Given:
Average Length of Gila Monster = 0.608 m
Average Length of Chuckwalla = 0.395 m
We need to find the number of times the Gila monster is as the Chuckwalla.
Solution:
Now we know that;
To find the number of times the Gila monster is as the Chuckwalla we will divide the Average Length of Gila Monster by Average Length of Chuckwalla.
framing in equation form we get;
number of times the Gila monster is as the Chuckwalla =
Rounding to nearest hundredth's we get;
number of times the Gila monster is as the Chuckwalla = 1.54
Hence Gila Monster is 1.54 times that of Chuckwalla.