We are asked in the problem to evaluate the integral of <span>(cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate
2005/cos^2005x dx which is equal to 2005 sec^2005 x since sec is the inverse of cos. The integral of this function when n >3 is equal to I=</span><span>∫<span>sec(n−2)</span>xdx+∫tanx<span>sec(n−3)</span>x(secxtanx)dx
Then,
</span><span>∫tanx<span>sec(<span>n−3)</span></span>x(secxtanx)dx=<span><span>tanx<span>sec(<span>n−2)</span></span>x/(</span><span>n−2)</span></span>−<span>1/(<span>n−2)I
we can then integrate the function by substituting n by 3.
On the first term csc^2 2005x / cos^2005 x we can use the trigonometric identity csc^2 x = 1 + cot^2 x to simplify the terms</span></span></span>
It’s 3, absolute value makes everything positive
(2x^2-x^2)= x^2
(1+7) = 8
X^2 + 8
Answer:
48
Step-by-step explanation:
find 60 on the y axis (for maths) then draw a line to where it meets the line, and see what value it gives. it gives us 48
Answer:
7.00+2.50x>48.00
Step-by-step explanation:
He cant spend more than 48.00 so he'll have to spend less than or equal to 48.00
