Answer:
-5y
Step-by-step explanation:
15 = 3×5
55 = 5×11
-15xyz = -1 × 3 × 5 × x × y × z
-55xy² = -1 × 5 × 11 × x × y²
-55yz = -1 × 5 × 11 × y × z
HCF = multiply all common factors with the lowest power amongst all 3 expressions
HCF = -1 × 5 × y = -5y
Answer:
Cost = RM 857143
Loss = RM 107143
Step-by-step explanation:
<u>Given:</u>
- Selling price SP = RM 750000
- Loss% = 12.5
- Cost price CP = x
<u>Cost price is found as:</u>
- SP = CP - 12.5%
- 750000 = x - 12.5%
- 750000= x*(100-12.5)/100
- 750000= 0.875x
- x= 750000/0.875
- x≈ RM 857143
<u>Loss is:</u>
- RM 857143 - 750000 = RM 107143
Answer:
for number one, look at the screenshot attached, that should help
Step-by-step explanation:
![\\ \sf{:}\implies side=\sqrt[3]{14}](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%7B%3A%7D%5Cimplies%20side%3D%5Csqrt%5B3%5D%7B14%7D)
Now
Cut it into 10 parts as per question(Open side means five sides hence it will be 5×2=10)
Now divide by previous side
Option D
Answer:
The expression for her balance is "B(t) = -75*t + 1500". It'll take her 20 months to pay off the loan.
Step-by-step explanation:
We are looking for a function that has the following points:
B(0) = 1500
B(4) = 1200
B(7) = 975
Between B(4) and B(7), there was a variation of 3 months and a variation of -225 on her balance, thefore for each month that passed there was a variation of -75. Thefore, the expression for her ballance is:
B(t) = -75*t + 1500
To check if this expression is valid, we will apply the values provided on the problem:
B(0) = -75*0 + 1500 = 1500 (valid)
B(4) = -75*4 + 1500 = -300 + 1500 = 1200 (valid)
B(7) = -75*7 + 1500 = -525 + 1500 = 975 (valid)
When she pays of her loan, B(t) = 0, so we need to solve for t as shown below:
B(t) = -75*t + 1500 = 0
-75*t + 1500 = 0
75*t = 1500
t = 1500 / 75 = 20 months
It'll take her 20 months to pay the loan.
