Question

Please answer a question the images.

Answer 1

The distribution of the animals in the coral reef is an illustration of probability

The most likely animal

The distribution of the animals is given as:

Blue fish = 3

Yellow fish = 7

Sea turtle = 1

Eels = 3

The animal with the highest frequency is the most likely animal.

Hence, the Yellow fish is the most likely animal.

Which is more likely?

From the question, we have:

Blue fish = 3

Eels = 3

Both animals have the same frequency.

This means that Riley has equal chance of seeing a blue fish and an eel.

The probability of seeing an animal with fins

The animal with fins are:

Blue fish = 3

Yellow fish = 7

So, the probability is:

$p = \frac{3 + 7}{3 + 7 + 1 + 3}$

$p = \frac{10}{14}$

Simplify

$p = \frac 57$

Hence, the probability of seeing an animal with fins is 5/7

The least likely animal

The animal with the least frequency is:

Sea turtle = 1

So, the likelihood is:

$p = \frac 1{14}$

Hence, the sea turtle has the least likelihood of 1/14

Animals with equal likelihood

The Blue fish and the Eels have the same frequency of 3

This means that animals have equal likelihood

The probability of seeing each animal

We have:

Blue fish = 3

Yellow fish = 7

Sea turtle = 1

Eels = 3

Express as probability

Blue fish = 3/14

Yellow fish = 7/14

Sea turtle = 1/14

Eels = 3/14

Express the fractions as decimals

Blue fish = 0.214

Yellow fish = 0.500

Sea turtle = 0.071

Eels = 0.214

So, their likelihoods are:

Blue fish = Equally likely

Yellow fish = Certainly likely

Sea turtle = Unlikely

Eels = Equally likely

Read more about probabilities at:

brainly.com/question/25870256