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Monica [59]
3 years ago
12

What width would you choose for the pdf?

Computers and Technology
1 answer:
MatroZZZ [7]3 years ago
8 0

Answer:

I would go for a width of 8.27 inches

Explanation:

The width of your PDF file depends on the project you are working on as well as your use case. Putting that aside, you are always better off making the dimensions of your PDF the same as the dimensions of A4 printing paper, which is 8.27 inches or 21 centimeters (2480 pixels). This is because A4 is the most common printing paper used and will make organization and printing less of a hassle.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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Olivia wants to change some settings in Outlook. What are the steps she will use to get to that function? open Outlook → File →
Rainbow [258]

Answer:

C.

Explanation:

edg 2020

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3 years ago
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ImmuneEarth, a research and development company, has "eradicate all diseases" as its motto. It has numerous departments that res
anastassius [24]

Answer:

Grid computing.

Explanation:

Grid computing is a study utilizing Immune Earth to test AIDS treatment because the following are the reasons that describe the answer is true about the scenario.

  • Grid computing seems to be a scattered network with a vast amount for systems linked to handle a difficult issue.
  • Systems can be linked straightly or through organized systems.

Other options are incorrect.

  • Green computing is not the correct answer according to the scenario because the usage of systems and its energy is socially safe and economically sustainable.
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4 0
4 years ago
Which of the following is not true about network design?Group of answer choicesIn designing LAN networks, network designers tend
sergey [27]

Answer:

In designing LAN networks, network designers tend to design err on the side of providing for less capacity than what is currently necessary.

Explanation:

In designing LAN networks, network designers tend to design err on the side of providing for less capacity than what is currently necessary is not true about network design.

8 0
3 years ago
[20 pts] Write the function rectangle(perimeter, area), which takes two positive integers, perimeter and area. It returns an int
MrRissso [65]

Hi, you haven't provided the programing language in which you need the code, I'll explain how to do it using Python, and you can follow the same logic to make a program in the programing language that you need.

Answer:

import math

def rectangle(perimeter, area):

   l1_1 = (perimeter+math.sqrt((perimeter**2)-(16*area)))/4

   l1_2 = (perimeter-math.sqrt((perimeter**2)-(16*area)))/4

   l2_1 = area/l1_1

   l2_2 = area/l1_2

   print(l1_1,l2_1)

   print(l1_2,l2_2)

   if l1_1.is_integer() and l2_1.is_integer() and l1_1>0 and l2_1>0:

       return(int(max(l1_1,l2_1)))

   elif l1_2.is_integer() and l2_2.is_integer() and l1_2>0 and l2_2>0:

       return(int(max(l1_2,l2_2)))

   else:

       return(None)

Explanation:

  • We import math to make basic operations
  • We define the rectangle function that receives perimeter and area
  • We calculate one of the sides (l1_1) of the rectangle using the quadratic equation to solve 2h^2 - ph + 2a = 0
  • We calculate the second root of the quadratic equation for the same side (l1_2)
  • We calculate the second side of the rectangle using the first root on w = a/h
  • We calculate the second side of the rectangle using the second root on w= a/h
  • We verify that each component of the first result (l1_1, l2_1) is an integer (using the build-in method .is_integer) and greater than 0, if True we return the maximum value between them (using the max function) as w
  • If the first pair of sides evaluate to False we check the second root of the equation and if they meet the specification we return the max value
  • if all the if statements evaluate to false we return None to indicate that not positive or integer sides were found

7 0
3 years ago
. Mercury, Venus, Earth, and Mars are the closest planets to the Sun
DIA [1.3K]

Answer:

<h3>True</h3><h2>Mercury  is the nearest</h2>

Explanation:

I hope this helps

4 0
3 years ago
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