Question

Design and implement an application that reads an integer value representing a year from the user. The purpose of the program is to determine if the year is a leap year (and therefore has 29 days in February) in the Gregorian calendar. A year is a leap year if it is divisible by 4, unless it is also divisible by 100 but not 400. For example, the year 2003 is not a leap year, but 2004 is. The year 1900 is not a leap year because it is divisible by 100, but the year 2000 is a leap year because even though it is divisible by 100, it is also divisible by 400. Produce an error message for any input value less than 1582 (the year the Gregorian calendar was adopted).

Answer 1

Answer :

Written in java

import java.util.Scanner;

public class Main{

   public static void main(String[] args) {

       int year;

       Scanner scanner = new Scanner(System.in);

       System.out.print("Please enter a year\n\n");

       year = scanner.nextInt();

       while (year < 1582) {

           System.out.print("\nPlease enter a different year above 1582\n");

           year = scanner.nextInt();

       }

       if (year % 4 == 0) {

           if(year % 100 ==0 && year % 400 != 0){

                   System.out.println(year + " is not a leap year\n\n");

           }else {

               System.out.println(year + " is a leap year\n");

           }

       } else {

           System.out.println(year + " is not a leap year\n\n");

       }

   }

}