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AnnZ [28]
3 years ago
15

What is 1/5 of 75? And how do you get that answer?

Mathematics
1 answer:
Elina [12.6K]3 years ago
7 0
Change the fraction to a percentage first. It'll be easier.

1/5 is equal to 20%.
"What is 20% of 75?" is now the question.

Now, we set up the problem.

\frac{part}{whole} = \frac{percent}{100}

The part will be 'x', since it is unknown, and 75 is the whole. 20% (1/5) will be the percent, obviously.

Here's a tip: If you can't find what the whole is, it usually follows 'of'.

Fill in the blanks.
\frac{x}{75} = \frac{20}{100}\\\\cross\ multiply\\\\75\times20=1500\\100\times x=100x \\\\1500=100x\\x=15


15 is 1/5 of 75.
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Marysya12 [62]

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Step-by-step explanation:

Let us revise the sine rule

In ΔABC:

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  • AB is opposite to ∠C
  • BC is opposite to ∠A
  • AC is opposite to ∠B

Let us use this rule to solve the problem

In ΔABC:

∵ m∠A = 45°

∵ m∠C = 30°

- The sum of measures of the interior angles of a triangle is 180°

∵ m∠A + m∠B + m∠C = 180

∴ 45 + m∠B + 30 = 180

- Add the like terms

∴ m∠B + 75 = 180

- Subtract 75 from both sides

∴ m∠B = 105°

∵ \frac{AB}{sin(C)}=\frac{BC}{sin(A)}

∵ AB = 5\sqrt{2}

- Substitute AB and the 3 angles in the rule above

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- By using cross multiplication

∴ (BC) × sin(30) = 5\sqrt{2} × sin(45)

∵ sin(30) = 0.5 and sin(45) = \frac{1}{\sqrt{2}}

∴ 0.5 (BC) = 5

- Divide both sides by 0.5

∴ BC = 10 units

∵ \frac{AB}{sin(C)}=\frac{AC}{sin(B)}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{AC}{sin(105)}

- By using cross multiplication

∴ (AC) × sin(30) = 5\sqrt{2} × sin(105)

∵ sin(105) = \frac{\sqrt{6}+\sqrt{2}}{4}

∴ 0.5 (AC) = \frac{5+5\sqrt{3}}{2}

- Divide both sides by 0.5

∴ AC = 5+5\sqrt{3} units

BC is 10 units and AC is 5+5\sqrt{3} units

Learn more:

You can learn more about the sine rule in brainly.com/question/12985572

#LearnwithBrainly

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