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dsp73
2 years ago
13

If there are 4 trucks for every 5 cars how many trucks and cars are there?

Mathematics
2 answers:
Rom4ik [11]2 years ago
8 0

Answer:

Step-by-step explanation:

^^there are 20 Trucks in total  And 5 cars

Roman55 [17]2 years ago
8 0

Answer:

8 trucks and 10 cars

12 trucks and 15 cars

16 trucks and 20 cars

20 trucks and 25 cars

24 trucks and 30 cars

Step-by-step explanation:

Basically any of those would be correct

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A bottle is filled with saline solution for eyes, is the bottle more likely to hold 15 milliliters of solution or 1 liter of sol
Gnesinka [82]
The bottle is more likely to hold 15 milliliters

hope this helped
3 0
3 years ago
Is π^2 greater or less than 7.2?
STatiana [176]

Answer:

less than

Step-by-step explanation:

Well pi divided by 2 is 1.57 and you need to figure out if 7.2 is greater than or less than pi^2 aka 1.57 so theres your ansewr

4 0
2 years ago
Read 2 more answers
Please help me figure this one out !!!
strojnjashka [21]
These are "composite" functions.
g(x+a)  means insert (x+a) into g(x) to replace every x:
g(x+a) - g(x) = -5(x+a)^2 +4(x+a) +5x^2 - 4x
 = -5(x^2 + 2ax + a^2) +4x +4a + 5x^2 - 4x
Now just Multiply and sum up the answer.

5 0
3 years ago
Tell whether the triangle with the given side lengths is a right triangle.
raketka [301]
It is not a right triangle
6 0
2 years ago
The partial fraction decomposition of 9 x 11 6 x 2 23 x 21 can be written in the form of f ( x ) 2 x 3 g ( x ) 3 x 7 , where
svlad2 [7]

Answer:

f(x) = -1

g(x) =6

\frac{-1}{2x + 3} + \frac{6}{3x + 7}

Step-by-step explanation:

The question is unreadable, however the real polynomial is:

The polynomial fraction is:

P = \frac{9x + 11}{6x^2 + 23x + 21}

And the decomposition is:

\frac{f(x)}{2x + 3} + \frac{g(x)}{3x + 7}

The solution is as follows:

P = \frac{f(x)}{2x + 3} + \frac{g(x)}{3x + 7}

Substitute the expression for P

\frac{9x + 11}{6x^2 + 23x + 21} = \frac{f(x)}{2x + 3} + \frac{g(x)}{3x + 7}

Expand the numerator of the polynomial

\frac{9x + 11}{(2x + 3)(3x + 7)} = \frac{f(x)}{2x + 3} + \frac{g(x)}{3x + 7}

Take LCM

\frac{9x + 11}{(2x + 3)(3x + 7)} = \frac{f(x)*(3x + 7) + g(x)*(2x + 3)}{(2x + 3)(x + 7)}

Cancel out both denominators

9x + 11} = f(x)*(3x + 7) + g(x)*(2x + 3)

Represent f(x) as A and g(x) as B

9x + 11} = A*(3x + 7) + B*(2x + 3)

Open bracket

9x + 11} = 3Ax + 7A + 2Bx + 3B

9x + 11} = 3Ax + 2Bx+ 7A  + 3B

9x + 11} = (3A + 2B)x+ 7A  + 3B

By comparison:

3A + 2B = 9 ---- (1)

7A  + 3B =11 ---- (2)

Make B the subject in (1)

B = \frac{9 - 3A}{2}

Substitute B = \frac{9 - 3A}{2} in (2)

7A + 3(\frac{9 - 3A}{2}) = 11

Multiply through by 2

2*7A +2* 3(\frac{9 - 3A}{2}) = 11*2

14A + 3(9 - 3A) = 22

14A + 27 - 9A = 22

Collect Like Terms

14A - 9A = 22-27

5A = -5

A = \frac{-5}{5}

A = -1

Recall that:

B = \frac{9 - 3A}{2}

B = \frac{9 - 3 * -1}{2}

B = \frac{9 + 3}{2}

B = \frac{12}{2}

B = 6

A = -1 and B = 6

3A + 2B = 9 ---- (1)

7A  + 3B =11 ---- (2)

So:

f(x) = A

f(x) = -1

g(x) =B

g(x) =6

And the decomposition is:

\frac{-1}{2x + 3} + \frac{6}{3x + 7}

6 0
2 years ago
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