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sveticcg [70]
3 years ago
13

THE IMAGE DOWN BELOW MATH PLEASE HELP ME WITH THIS ALEGEBRA IM CRYING YALL

Mathematics
1 answer:
Fittoniya [83]3 years ago
4 0

Answer:

25% increase

Step-by-step explanation:

final value (20) -minus- starting value (16)

-------------------divided by ----------------             times * 100

starting value (20)

4

---  x 100

20

25%

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Find the volume of the cylinder
julsineya [31]

The volume of the cylinder is

62.83 units³

3 0
3 years ago
Read 2 more answers
A clock has a face in the shape of a circle the distance across a circle is 12 inches what is the area of the clock face in squa
Oksanka [162]

Answer:

18.84 square inches

Step-by-step explanation:

Distance across = diameter. The area formula for circles is A= πr. r in here means radius which is 6 inches (half of diameter). π is generally 3.14 or 22/7 depending on the question. multiply the value of π and 6, then you get the answer.

4 0
3 years ago
Somebody help thanks
slamgirl [31]
Really simple, All you have to do is find out how many meters are in a kilometer, which is 1000 meters, and then you have to multiply 1000 with 190 which is 190000. Hope i helped!
6 0
3 years ago
The weights of certain machine components are normally distributed with a mean of 8.04 g and a standard deviation of 0.08 g. Fin
NISA [10]

Answer:

The bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

Step-by-step explanation:

We are given that

Mean, \mu=8.04 g

Standard deviation, \sigma=0.08g

We have to find the two weights that separate the top 3% and the bottom 3%.

Let x be the weight of  machine components

P(Xx_2)=0.03

P(X

=0.03

From z- table we get

P(Z1.88)=0.03

Therefore, we get

\frac{x_1-8.04}{0.08}=-1.88

x_1-8.04=-1.88\times 0.08

x_1=-1.88\times 0.08+8.04

x_1=7.8896

\frac{x_2-8.04}{0.08}=1.88

x_2=1.88\times 0.08+8.04

x_2=8.1904

Hence, the bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

5 0
3 years ago
Question one pls<br> algebra 2<br> logarithms
nirvana33 [79]

Condense the logarithm on the right side:

3\log_b(p)-\left(2\log_b(t)+\dfrac12\log_b(r)\right)

n\log_b(m)=\log_b(m^n) \implies \log_b(p^3)-\left(\log_b(t^2)+\log_b\left(r^{\frac12}\right)\right)

\log_b(m)+\log(n)=\log_b(mn) \implies \log_b(p^3)-\log_b\left(t^2r^{\frac12}\right)

\log_b(m)-\log(n)=\log_b\left(\dfrac mn\right) \implies \log_b\left(\dfrac{p^3}{t^2r^{\frac12}}\right)

So,

x=\dfrac{p^3}{t^2r^{\frac12}}

and r^{\frac12}=\sqrt{r}, which makes (4) the correct choice.

4 0
3 years ago
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