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Orlov [11]
3 years ago
11

Solve for x: 7x + 15 = 38

Mathematics
2 answers:
Dimas [21]3 years ago
8 0
The answer is 3.3 .........................





Alexeev081 [22]3 years ago
4 0
7x+15=38
7x=38-15
7x=23
x=23/7
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Solve x+y=7 and 3x-2y=11 using elimination
BartSMP [9]
X=5 and y =2.
Here's how you do it.
Multiply the first equation by -3, and the second one by 1.
add the equations to eliminate x.
then solve for y by dividing both sides by -5, which gives us 2.
to solve for x subsitute 2 in for y.

8 0
3 years ago
8 percent of what number is 2
Sedbober [7]
8%×n=2. 2÷8/100=2×100/8=100/4=25. so the answer is 25.
5 0
2 years ago
Please explain how to solve this (<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7Ba%5E5%20b%5E3%7D%20" id="TexFormula1" ti
olchik [2.2K]
2 is the base and (\sqrt[4][a^5 b^3]) is the exponent.

the 4 is called an index and it means to fi d the fourth root of the expression under the (\sqrt[][text]) symbol.\\a fourth root is a factor that was multiplied four times. ex: 2*2*2*2=16. the fourth root of 16 is two. \\when you do square roots, you take the number representing the factor out of the radical. anything else that is not a square root stays under. ex: \\([tex]\sqrt[9][text])\\([tex]\sqrt[3*3*3][text]) there is one set of two 3's so\\([tex]3\sqrt[3][text])\\with a fourth root, you look for groups of four. the symbol of that group is placed outside the radical. anything else stays in.\\ ([tex]\sqrt[4][a^5 b^3])

(\sqrt[4][a*a*a*a*a*b*b*b]) there is one group of 4 a's so

(a\sqrt[4][a* b^3])

there really isn't anything else to do to simplify the expression
5 0
2 years ago
4.
-Dominant- [34]

Answer:

All four

Step-by-step explanation:

SSS, SAS, ASA, and HL

7 0
2 years ago
2a +5 - 3a -12 please
chubhunter [2.5K]

Answer:

-7-a

Step-by-step explanation:

2a-3a +5-12

-a - 7

or -7-a

7 0
3 years ago
Read 2 more answers
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