Answer:
Jamar should hit the wall opposite to the side of the barrier(if there is a space), which will cause the ball to bounce off the wall at an angle and into Target.
Ok so
since we h ave
3.5=1 day's morning
and
2.3=1 day's afternoon
we need to add them to find 1 day and multiply by 6 (number of days)
that answer is not listted so we make into anohter form
this wold be
6 times (3.5 +2.3)
if we distributed
a(b+c)=ab+ac
6(3.5+2.3)=6 times 3.5+6 times 2.3
this is D
Answer:
m∡A = 100°
m∡B = 50°
m∡C = 30°
Step-by-step explanation:
let 'x' = m∡B; 50°
let '2x' = m∡A; 100°
let 'x-20' = m∡C; 30°
x + 2x + x - 20 = 180
4x - 20 = 180
4x = 200
x = 50
Answer:
(2) is the correct answer
Step-by-step explanation:
if you multiply the given equation by 3 you get answer (2):
3(4x - 3y) = 3(12)
12x - 9y = 36
Option A
The solution is ![(0, \frac{-1}{4})](https://tex.z-dn.net/?f=%280%2C%20%5Cfrac%7B-1%7D%7B4%7D%29)
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
3x + 6y = 1 ------ eqn 1
x - 4y = 1 ------ eqn 2
We have to find solution to system of equations
We can use substitution method
From eqn 2,
x = 1 + 4y -------- eqn 3
Substitute eqn 3 in eqn 1
3(1 + 4y) + 6y = 1
3 + 12y + 6y = 1
18y = 1 - 3
18y = -2
Divide both sides by 18
![y = \frac{-2}{18}\\\\y = \frac{-1}{4}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B-2%7D%7B18%7D%5C%5C%5C%5Cy%20%3D%20%5Cfrac%7B-1%7D%7B4%7D)
Substitute the above value of y in eqn 3
![x = 1 + 4 \times \frac{-1}{4}\\\\x = 1-1\\\\x = 0](https://tex.z-dn.net/?f=x%20%3D%201%20%2B%204%20%5Ctimes%20%5Cfrac%7B-1%7D%7B4%7D%5C%5C%5C%5Cx%20%3D%201-1%5C%5C%5C%5Cx%20%3D%200)
Thus solution is ![(0, \frac{-1}{4})](https://tex.z-dn.net/?f=%280%2C%20%5Cfrac%7B-1%7D%7B4%7D%29)