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3 years ago

Combine the like terms to create an equivalent expression: −2x−x+8

Mathematics

2 answers:

ehidna [41]3 years ago

7 0

Answer:

Step-by-step explanation:

negative 2x minus x would be negative 2 plus postive 8 = 6

larisa [96]3 years ago

6 0

Answer:

Since the "x"'s match you can put them together! so (-2x)-(x)= -3x . When we add/subtract variables like "x" we only subtract/add the numbers in front of the variables and also, a variable by itself is just representing 1 of that variable that's why we can say that x means 1x and we can subtract -2 by 1. Now we are done because there are no more like numbers left we can just leave the expression as --> -3x+8

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stealth61 [152]

Answer:

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Step-by-step explanation:

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Answer: 18/5

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A long jumper lifts off 3 m after starting his run, and lands 6 m later. When he is 8 m from the start line, he is 5 cm above an

slega [8]

Answer:

The equation of the parabola that models the path of the long jumper through the air is $y = -x^{2}+12\cdot x -27$ .

Step-by-step explanation:

Mathematically, we know that parabolas are second-order polynomials and every second-order polynomials, also known as quadratic functions, can be constructed by knowing three different points of the curve. The standard form of the parabola is:

$y = a\cdot x^{2}+b\cdot x + c$

Where:

$x$ - Horizontal distance from the start line, measured in meters.

$y$ - Height of the long jumper, measured in meters.

$a$ , $b$ , $c$ - Polynomial constants, measured in $\frac{1}{m}$ , dimensionless and meters, respectively.

If we know that $(x_{1},y_{1}) = (3\,m, 0\,m)$ , $(x_{2},y_{2}) = (8\,m, 0.05\,m)$ and $(x_{3}, y_{3}) = (9\,m, 0\,m)$ , this system of linear equations is presented below:

$9\cdot a + 3\cdot b + c = 0$ (Eq. 1)

$81\cdot a + 9\cdot b + c = 0$ (Eq. 2)

$64\cdot a + 8\cdot b + c = 0.05$ (Eq. 3)

The coefficients of the polynomial are, respectively:

$a = -\frac{1}{100}$ , $b = \frac{3}{25}$ , $c = -\frac{27}{100}$

The equation of the parabola that models the path of the long jumper through the air is $y' = -\frac{1}{100}\cdot x^{2}+\frac{3}{25}\cdot x -\frac{27}{100}$ .