All categories

3 years ago

.002 is 1/10 of what

1 answer:

5 0

Let the unknown number be x. Then (1/10)x = 0.002. To solve for x, multiply both sides by 1000 to remove the decimal fraction 0.002.

Then 1000(1/10)x = 1000(0.002), or 100x = 2. Dividing both sides by x returns

x=100/2, or x= 50 (answer)

You might be interested in

Is this correct, my teacher graded it and i think it is correct

aliina [53]

Yes I think that is the correct answer

4 0

2 years ago

Read 2 more answers

Dominique and his friends are going on a road trip that is 381.1 miles long. If they have 214.43 miles until their destination,

Kisachek [45]

Answer:

166.67 miles

Step-by-step explanation: 381.1 = x + 214.43

381.1-214.43 = 166.67 miles

5 0

2 years ago

Read 2 more answers

A construction crew must build 4 miles of road in one week. On Monday, they build 12 mile of road. On Tuesday, they build 13 mil

Julli [10]

$\frac{19}{6}$ many more miles of road are left to build .

<u>Step-by-step explanation:</u>

Here we have , A construction crew must build 4 miles of road in one week. On Monday, they build 1/2 mile of road. On Tuesday, they build 1/3 mile of road. We need to find that How many more miles of road are left to build . Let's find out:

On Monday, they build 1/2 mile of road.
On Tuesday, they build 1/3 mile of road.

Let Miles of road left to build is x So,

⇒ $\frac{1}{2} +\frac{1}{3} +x = 4$

⇒ $x = 4 - (\frac{1}{2} +\frac{1}{3})$

⇒ $x = 4 - (\frac{1(3)+1(2)}{6} )$

⇒ $x = 4 - (\frac{5}{6} )$

⇒ $x = (\frac{4(6)-5}{6} )$

⇒ $x = \frac{24-5}{6}$

⇒ $x = \frac{19}{6}$

Therefore, $\frac{19}{6}$ many more miles of road are left to build .

5 0

3 years ago

Read 2 more answers

How to find matrics M

makkiz [27]

$\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -4M=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\qquad(*) \\\\M=\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]\to4M=\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]$

$(*)\qquad\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\\\\left[\begin{array}{ccc}9-4a&7-4b\\-4-4c&2-4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\.\qquad\qquad\qquad\qquad\ \ \ \Downarrow\\(_{11})\qquad9-4a=-3\ \ \ |-9\\-4a=-12\ \ \ \ |:(-4)\\a=3\\\\(_{12})\qquad7-4b=3\ \ \ \ |-7\\-4b=-4\ \ \ \ |:(-4)\\b=1$

$(_{21})\qquad-4-4c=4\ \ \ \ |+4\\-4c=8\ \ \ \ |:(-4)\\c=-2\\\\(_{22})\qquad2-4d=-18\ \ \ \ |-2\\-4d=-20\ \ \ \ \ |:(-4)\\d=5\\\\Answer:\ A.\ M=\left[\begin{array}{ccc}3&1\\-2&5\end{array}\right]$

3 0

3 years ago

Fill in the blank with the correct term or number to complete the sentence.

Furkat [3]

Mentally, they are numbers in which you can do mental math with since they are whole numbers

4 0

3 years ago