All categories

4 years ago

PLEASE HELP ME!!!!!

1 answer:

5 0

We know that

if Ray RT bisects QRS
then
the ray RT divide into two equal parts the ∡QRS
so
∡QRT=∡TRS
∡QRT=∡QRS/2-------> 64°/2------> 32°
∡QRT=32°
∡TRS=32°

the answer is
the measures of QRT and TRS is 32°

You might be interested in

Leta is making strawberry almond salad for a party for every head of lettuce that she uses she adds 5 ounces of almonds and 10 s

Jet001 [13]

15 heads of lettuce and 150 strawberry’s

7 0

4 years ago

Factor 15z^2+17z-18 please show work

siniylev [52]

There is no common factor between 15, 17 and 18 because 17 is prime.

15z² +17z - 18 =

d = 17² - 4.15.-18

d = 289 + 1080

d = 1369

z = (-17 +/- \/1369) : 2 * 15

z = (-17 + 37) : 30

z' = 20 : 30 = 2/3

z" = (-17 - 37) : 30

z" = -54 : 30 = -1.8

<><

7 0

3 years ago

The base of an aquarium with given volume V is made of slate and the sides are made of glass. If slate costs five times as much

Y_Kistochka [10]

Answer:

x = ∛ 2*V/5

y = ∛ 2*V/5

h = V/ ∛ 4*V²/25

Step-by-step explanation:

Dimensions of the aquarium base is x*y

We call c₁ cost per unit area of the sides, then cost per unit area of slate is equal 5c₁.

let call h the height of the aquarium then volume of the aquarium is:

V = x*y*h where h = V / x*y

As the base is a rectangular one there are 2 sides x*h . and 2 sides y*h

According to this:

Ct (cost of aquarium ) = cost of the base + cost of the sides

cₐ ( cost of the base) = 5*c₁*x*y

c₆ (cost of the sides ) = c₁*2*x*h + c₁*2*y*h

C(t) = 5*c₁*x*y +2* c₁*x* V/x*y + 2* c₁*y* V/x*y or

C(t) = 5*c₁*x*y + 2*c₁*V/y *2*c₁* V/x

Taking partial derivatives en x and y we have:

C´(x) = 5*c₁*y - 2*c₁*V/x²

C´(y) = 5*c₁*x - 2*c₁*V/y²

C´(x) = C´(y) ⇒ 5*c₁*y - 2*c₁*V/x² = 5*c₁*x - 2*c₁*V/y²

or 5*y - 2*V/x² = 5*x - 2*V/y²

(5*y*x² - 2*V)/x² = ( 5*y²x - 2*V) /y²

(5*y*x² - 2*V)*y² = ( 5*y²x - 2*V)*x²

5*y³*x² - 2*V*y² = 5*y²x³ - 2*V*x²

5*y³*x² - 5*y²x³ = 2*V * ( y² - x²)

by symmetry x = y

Then using x = y and plugging that value on the derivatives

C´(x) = 5*c₁*y - 2*c₁*V/x²

C´(x) = 5*c₁*x - 2*c₁*V/x²

C´(x) = 0 ⇒ 5*c₁*x - 2*c₁*V/x² = 0

5*x - 2*V/x² = 0 ⇒ 5*x³ - 2*V = 0 ⇒ 5*x³ = 2*V ⇒ x³ = 2*V/5

x = ∛ 2*V/5 and y = ∛ 2*V/5 and h = V/ x*y h = V/ ∛ 4*V²/25

7 0

3 years ago

What is the slope of the line represented by the equation –5x 2y= 10 ?

Sladkaya [172]

In the equation y=mx+b, the variable m represents the slope of the line. Therefore, the equation -5x+2y=10 can be rearranged into 2y=5x+10. Isolate the y to get y=2.5x+5. The slope of the line is 2.5

7 0

3 years ago

Show your work: Express 160 pounds (lbs) in kilograms (kg). Round to the nearest hundredths.

andrew-mc [135]

Answer:

160 lbs = 72.57kg

Step-by-step explanation:

This can be solved as a rule of three problem.

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.

Unit conversion problems, like this one, is an example of a direct relationship between measures.

Each lb has 0.45kg. How many kg are there in 160lbs. So:

1lb - 0.45kg

160 lbs - xkg

$x = 0.45*160$

$x = 72.57$ kg

160 lbs = 72.57kg

4 0

3 years ago