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3 years ago

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Which of the following does not cycle into the atmosphere? a. the carbon cycle b. the phosphorus cycle c. the nitrogen cycle d.

the oxygen cycle Please select the best answer from the choices provided A B C D

2 answers:

amm18123 years ago

7 0

Answer:

its B

Step-by-step explanation:

Aleksandr-060686 [28]3 years ago

3 0

Answer: b. the phosphorus cycle

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You are constructing triangle ABC given the line segments AB and AC and ∠A. The first thing you do is copy segment AC. Next, you

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Answer:

C) Copy AB

Step-by-step explanation:

The general idea is that you copy one segment, then the angle (so you know which direction the other segment goes), then the second segment. Finally, you connect the ends of the segments to complete the triangle.

The given description says you've done the first two parts of this, so you must mark off the length of segment AB in the direction you just constructed. That is, you must ...

Copy AB.

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In the attached figure, the construction did segment AB first, and is about to do segment AC next. The idea is the same. Swap points B and C in your mind to match the description in the problem statement.

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How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi

ryzh [129]

<u>Answer</u>:

3003 number of 5-member chess teams can be chosen from 15 interested players.

<u>Step-by-step explanation:</u>

Given:

Number of the interested players = 15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formula $nCr = \frac{n!}{r!(n - r)!}$

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now we have n = 15 and r = 5

Substituting the values,

$15C_5 = \frac{15!}{5!(15- 5)!}$

$15C_5 = \frac{15!}{5!(10)!}$

$15C_5 = \frac{15!}{5!(10)!}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11}{(5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{360360}{120}$

$15C_5 = 3003$

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