What is the equation of the following line? Be sure to scroll down first to see all answer options.

Please help me out!!!!!!!! :)

ozzi

Answer:I think it is 73 degrees

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

A farmer has two types of milk, one that is 24% butterfat and another which is 18% butterfat. How much of each should he use to

iVinArrow [24]

Answer:

i have autism and adhd and add and dmdd so plz dont yell at me that i did not answer!!!!!

but please have a beautiful weekend!! :)

Step-by-step explanation:

3 0

2 years ago

Weights of cars passing over a bridge part 2

DaniilM [7]

Step-by-step explanation:

The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.

Given:

mean, mu = 3550 lbs (hope I read the first five correctly, and it's not a six)

standard deviation, sigma = 870 lbs

weights are normally distributed, and assume large samples.

Probability to be estimated between W1=2800 and W2=4500 lbs.

Solution:

We calculate Z-scores for each of the limits in order to estimate probabilities from tables.

For W1 (lower limit),

Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069

From tables, P(Z<Z1) = 0.194325

For W2 (upper limit):

Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954

From tables, P(Z<Z2) = 0.862573

Therefore probability that weight is between W1 and W2 is

P( W1 < W < W2 )

= P(Z1 < Z < Z2)

= P(Z<Z2) - P(Z<Z1)

= 0.862573 - 0.194325

= 0.668248

= 0.67 (to the hundredth)

6 0

2 years ago

Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance. For what fraction of

Kruka [31]

Answer:

Lola was in lead for $\frac{6}{25}$ of a mile.

Step-by-step explanation:

We have been given that Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance.

To find the fraction of a mile for which Lola was in the lead, we need to find 4/5 of 3/10 as:

$\text{Fraction for which Lola was in lead}=\frac{3}{10}\times\frac{4}{5}$

$\text{Fraction for which Lola was in lead}=\frac{3}{5}\times\frac{2}{5}$

$\text{Fraction for which Lola was in lead}=\frac{3\times2}{5\times5}$

$\text{Fraction for which Lola was in lead}=\frac{6}{25}$

Therefore, Lola was in lead for $\frac{6}{25}$ of a mile.

7 0

2 years ago

Please help me find the total area of the composite figure below (geometry)

Akimi4 [234]

Answer:

lw + $\frac{1}{2}$ × π × $(\frac{l}{2} )^{2}$ ⇒ Answer D is correct

Step-by-step explanation:

First, let us find the area of the semi-circle.

Area = $\frac{1}{2}$ × π × r²

Given that,

diameter of the semi-circle is ⇒ l

∴ radius ⇒ l / 2

Let us find it now.

Area = $\frac{1}{2}$ × π × r²

Area = $\frac{1}{2}$ × π × $(\frac{l}{2} )^{2}$

Secondly, let us find the area of the rectangle.

Area = length × width

Given that,

length ⇒ l

width ⇒ w

Let us find it now.

Area = length × width

Area = l ×w

Area = lw

And now let us find the total area.

Total area = Area of the rectangle + Area of the semi - circle

Tota area = lw + $\frac{1}{2}$ × π × $(\frac{l}{2} )^{2}$

8 0

1 year ago