Answer:
Step-by-step explanation:
The equation of a straight line can be represented in the slope intercept form as
y = mx + c
Where
m = slope = (change in the value of y on the vertical axis) / (change in the value of x on the horizontal axis)
The equation of the given line is
9x+7y=4
7y = 4 - 9x = -9x + 4
y = -9x/7 + 4/7
Comparing with the slope intercept form, slope = -9/7
If the line passing through the given point is perpendicular to the given line, it means that its slope is the negative reciprocal of the slope of the given line.
Therefore, the slope of the line passing through (7,-4) is 7/9
To determine the intercept, we would substitute m = 7/9, x = 7 and y = - 4 into y = mx + c. It becomes
- 4 = 7/9×7 + c = 49/9 + c
c = - 4 - 49/9
c = - 85/9
The equation becomes
y = 7x/9 - 85/9
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from what I remember from what my teacher taught me was that its nonlinear. I'm 98% sure its nonlinear
I'm am so sorry if I get it wrong. I'm apologizing ahead. if you want you can get the points back I dont mind because I feel bad when I get things wrong but I'm pretty sure its non linear
Answer:
C) y+6=3/2(x-2)
Step-by-step explanation:
y-y1=m(x-x1)
m=slope & (x1, y1) is a point on the line
m=(y2-y1)/(x2-x1)
m=(-3-(-6))/(4-2)
m=(-3+6)/2
m=3/2
y-(-6)=3/2(x-2)
y+6=3/2(x-2)