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Sergio [31]
2 years ago
15

If you remove the biological (etiologic) contamination hazards through destroying microorganisms and their toxins, what mechanis

m of decontamination did you use?
Biology
2 answers:
guajiro [1.7K]2 years ago
8 0

Answer:

The correct answer is mechanism of disinfection.

Explanation:

In case, when the microbes are killed, and the toxins are also eliminated, it is clearly evident that a technique of disinfection has been employed in order to decontaminate the region or the area. The methods of disinfection generally comprise two methods, that is, physical and chemical. In the physical method, the application of physical agents is done, while in the chemical methods, use of chemical agents like chlorine is done. The process of disinfection does not completely kill the microbes, however, it helps in preventing the growth of microbes and toxins.

qaws [65]2 years ago
7 0
Removing the biological (etiological) contamination hazards  by destroying microorganisms and their toxins is called the process of disinfection. It involves killing or preventing the growth bacteria. However, it does not eliminate all bacteria, there are some microorganisms that contains spores which are very resistant to disinfectants.<span />
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Answer:

25%

Explanation:

When looking at a pedigree remember that:

  • squares are males
  • circles are females
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Let us assign the symbol X⁺ to represent the dominant allele linked to the X-chromosome and expressing healthiness, and X⁻ to represent the recessive allele expressing the dissease.

According to this pedigree

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  • I2 is a healthy woman X⁺X⁻
  • we can see that among the progeny (generation II) there are two individuals affected (a boy and a girl) and one healthy girl. This means that the mother I2 is heterozygous for the trait.

So, having their genotypes we can know what are the probabilities of getting a son with DMD

Parentals)    YX⁻     x     X⁺X⁻  

Gametes)   Y     X⁻      X⁺     X⁻

Punnett square)

                        X⁺             X⁻

            X⁻      X⁺X⁻         X⁻X⁻    

            Y        X⁺Y           X⁻Y

F1)

  • The probabilities of getting a healthy daughter X⁺X⁻ are 25%
  • The probabilities of getting a healthy son X⁺Y are 25%
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  • The probabilities of getting a son with DMD X⁻Y are 25%
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