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Softa [21]
4 years ago
12

A class has 50 students. 20 students are playing basketball and rest are playing volleyball. The percent of the class playing ba

sketball is?
a) 20 percent
b) 40 percent
c) 60 percent ​
Mathematics
2 answers:
olga_2 [115]4 years ago
7 0
60% should be right because it’s out of 100 and 100 - 20 is 60
Sav [38]4 years ago
5 0

Answer:

60 percent

Step-by-step explanation:

so 50 is half of 100,right? so that means you can just multiply everything by 2 to make it easier. so then there are 100 students and 40 play basket ball. so that means 40 percent play basketball and that only leaves 60 remaining :)

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Can somebody solve this for me?
Komok [63]

Answer: C

Step-by-step explanation:

Solve by replacing the x

A. not true

12.5x

B. not true

-12.5(x)>50\\-12.5(4)>50\\-50>50

C. true

12.5x\leq 50\\12.5(4)\leq 50\\50\leq 50

D. not true

-12.5x\geq 50\\-12.5(4)\geq 50\\-50\geq 50

8 0
3 years ago
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A property sells for $620,000 two years after it was purchased. If the annual appreciation rate was 4%, how much did the origina
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3 years ago
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Which of the following points is a solution of the inequality y < |x-2|
blsea [12.9K]

it could be 2, 0 but I am not sure

7 0
4 years ago
Work out the area of this semicircle.Take pie to be 3.142 and give your answer to 2 decimal places 10cm
rosijanka [135]

Answer:

The area of the semi circle  A = 157.1 cm^2

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<em>Given radius of circle 'r' = 10 cm</em>

<em>The area of the circle formula </em>

<em>                                 </em>A = \pi (r)^{2}<em></em>

<em>The area of the semi circle formula </em>

                            A = \frac{\pi (r)^{2} }{2}

taking  π =3.142

                           A = 3.142 X \frac{(10)^2}{2}

On calculation , we get

                           A = 157.1 cm^2

<u><em>Final answer</em></u>:-

<em>The area of the semi circle  </em>A = 157.1 cm^2<em></em>

7 0
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Bas_tet [7]

Answer:

I think it is 6/7

Step-by-step explanation:

I am really bad at explaining but I'm not completely sure

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